Answer:
z ≈ 9.22
Step-by-step explanation:
Given the equations
2x-4y+4z-6w=4 ................ 1
6w-4x+4y-4z=-12 ...............2
6w+4x-2y+6z=64 ............... 3
4z+2w+6y-4x=56 ................ 4
We will first need to reduce the equation by cancelling out some variables.
Add equations 1 and 2 will give;
(2x-4x)+(-4y+4y)+(4z-4z)+ (-6w+6w) = 4+12
-2x +0 = 16
-2x = 16
x = -8
Also, equation 2 minus 3
6w-6w+(-4x-4x)+4y+2y+(-4z-6z) = 12-64
-8x+6y-10z = -52
-8(-8)+6y-10z = -52
64+6y-10z = -52
6y-10z = -52-64
6y-10z = -116
3y-5z = -58 ... 5
Equation 3 * 1 and eqn 4 * 3
6w+4x-2y+6z=64 ............... 3
4z+2w+6y-4x=56 ................ 4
6w+4x-2y+6z=64
12z+6w+18y-12x= 168
Subtracting both equations;
16x-20y-6z = -104
8x-10y-3z = -52
8(-8)-10y-3z = -52
-64-10y-3z = -52
-10y-3z = -52+64
-10y-3z = 12 ....... 6
equating 5 and 6 and solving simultaneously;
3y-5z = -58 ... 5 * 10
-10y-3z = 12 ....... 6 * 3
30y-50z = -580
-30y-9z = 36
Add both equations
-50z-9z = -580+36
-59z = -544
z = -544/-59
z = 9.22
Hence z ≈ 9.22
Ok so first we need to under stand that 60 minutes is equivalent to 1 hour, by knowing this we should be able to answer the following. Our first box which needs to be filled in asking how many hours are in 300 minutes, well let’s figure this out. So we know that in 60 minutes it will be equivalent to one hours, so in order to find how many minutes are in 300 minutes we would divide 300 by 60 which give a us 5. Therefore causing the second box to me 5 hours. Our next and final box is asking how many hours are in four minutes well this one is a little harder than our previous one but I’ll help you through it. By following the same procedure as we did the previous question we are going to divide 4 by 60 and we know that dividing like so we are going to get a decimal but that’s ok it’s going to give us the answer we need to fill in the box. By dividing like so we should get a long decimal that look that this 0.066666666666667. I am going to simply this down to 0.0667. Causing my last box to be 0.667.
Summary:
second box: 5 hours
Third box: 0.0667 hours
Hope this helps!!!
Please tell me if I have made an error, I enjoy learning from my mistakes:)
Have a great rest of your day❤️
Answer:
Step-by-step explanation:
Lets expand all the composite numbers into prime numbers.
Lets cancel 
from numerator and denominator.
Using laws of exponents , lets solve this.
![=> 3^{-3} \times 5^{[1 - (-2)]}](https://tex.z-dn.net/?f=%3D%3E%203%5E%7B-3%7D%20%5Ctimes%205%5E%7B%5B1%20-%20%28-2%29%5D%7D)
Option A:
Solution:
ABCD and EGFH are two trapezoids.
To determine the correct way to tell the two trapezoids are similar.
Option A:
AB = GF (side)
BC = FH (side)
CD = HE (side)
DA = EG (side)
So, is the correct way to complete the statement.
Option B: 
In the given image length of AB ≠ EG.
So, is the not the correct way to complete the statement.
Option C: 
In the given image length of AB ≠ FH.
So, is the not the correct way to complete the statement.
Option D: 
In the given image length of AB ≠ HE.
So, is the not the correct way to complete the statement.
Hence, is the correct way to complete the statement.
Answer:
40
Step-by-step explanation:
look at the picure for step by step explanation
