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3 years ago

NEEDING HELP ASAP PLEASE :( click on photo

Mathematics

1 answer:

LiRa [457]3 years ago

6 0

9514 1404 393

Answer:

(1, 1)

Step-by-step explanation:

Did you watch the video?

The y-coefficients have opposite signs and one is a multiple of the other. It is convenient to divide the second equation by 2 and add that to the first.

(5x -2y) +1/2(4x +4y) = (3) +1/2(8)

7x = 7 . . . . simplify

x = 1 . . . . . divide by 7

4(1) +4y = 8 . . . . substitute for x in the second equation

4y = 4 . . . . . . . . subtract 4

y = 1 . . . . . . . . . . divide by 4

The solution is (x, y) = (1, 1).

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Pls help i will give brainliest

Vladimir79 [104]

Answer:

the thrid one

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The probability that two people have the same birthday in a room of 20 people is about 41.1%. It turns out that

salantis [7]

Answer:

a) Let X the random variable of interest, on this case we know that:

$X \sim Binom(n=20, p=0.411)$

This random variable represent that two people have the same birthday in just one classroom

b) We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

$P(X\geq 1 ) = 1-P(X$

And we can find the individual probability:

$P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253$

And then:

$P(X\geq 1 ) = 1-P(X$

And since we want the probability in the 3 classes we can assume independence and we got:

$P= 0.99997^3 = 0.9992$

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

Part a

Let X the random variable of interest, on this case we know that:

$X \sim Binom(n=20, p=0.411)$

This random variable represent that two people have the same birthday in just one classroom

Part b

We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

$P(X\geq 1 ) = 1-P(X$

And we can find the individual probability:

$P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253$

And then:

$P(X\geq 1 ) = 1-P(X$

And since we want the probability in the 3 classes we can assume independence and we got:

$P= 0.99997^3 = 0.9992$

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

4 0

4 years ago

Consider the function f(x) = 3x and the function g, which is shown below.

VLD [36.1K]

Answer:

<em>B. The graph of g is the graph of f shifted 2 units down</em>

Step-by-step explanation:

<u>Graph of Functions</u>

We have two functions:

f(x)=3^x

g(x)=3^x-2

Since g(x)=f(x)-2 it will be represented as an identical graph as that for f(x), but vertically displaced 2 units down. Let's check it by plugging some points

f(0)=3^0=1

g(0)=3^0-2=-1

f(1)=3^1=3

g(1)=3^1-2=1

f(3)=3^3=27

g(3)=3^3-2=25

We can notice the values of g(x) are always 2 units below f(x), thus the correct answer is

B. The graph of g is the graph of f shifted 2 units down

7 0

3 years ago

12.5 percent of what number is 24

irina [24]

24 : 12.5/100 = 24 * 100/12.5 = 192;

3 0

3 years ago

5b 2 −6b−2 is prime TURE OR FALSE!! 100 POINTS PLEASE HELP!!!!

Ivan

The given quadratic expression; 5b² -6b -2 is prime because the discriminant is not a perfect square.

<h3>What is the discriminant of the expression?</h3>

According to the task content; it is required to identify if the expression is prime.

On this note, it follows that the discriminant of the expression can be evaluated as follows;

= 36 -(4× 5 × -2)

= 76.

Hence, the expression is prime since 76 is not a perfect square.