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2 years ago

NEEDING HELP ASAP PLEASE :( click on photo

Mathematics

1 answer:

LiRa [457]2 years ago

6 0

9514 1404 393

Answer:

(1, 1)

Step-by-step explanation:

Did you watch the video?

The y-coefficients have opposite signs and one is a multiple of the other. It is convenient to divide the second equation by 2 and add that to the first.

(5x -2y) +1/2(4x +4y) = (3) +1/2(8)

7x = 7 . . . . simplify

x = 1 . . . . . divide by 7

4(1) +4y = 8 . . . . substitute for x in the second equation

4y = 4 . . . . . . . . subtract 4

y = 1 . . . . . . . . . . divide by 4

The solution is (x, y) = (1, 1).

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Plz can any1 answer this question asap

vfiekz [6]

Answer:

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3 years ago

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Give the properties for the equation -2x 2 - y + 10x - 7 = 0.

Sladkaya [172]

Given:

The quadratic equation is

$-2x^2-y+10x-7=0$

To find:

The vertex of the given quadratic equation.

Solution:

If a quadratic function is $f(x)=ax^2+bx+c$ , then

$Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)$

We have,

$-2x^2-y+10x-7=0$

It can be written as

$-2x^2+10x-7=y$

$y=-2x^2+10x-7$ ...(i)

Here, $a=-2,b=10,c=-7$ .

$\dfrac{-b}{2a}=\dfrac{-10}{2(-2)}$

$\dfrac{-b}{2a}=\dfrac{-10}{-4}$

$\dfrac{-b}{2a}=\dfrac{5}{2}$

Putting $x=\dfrac{5}{2}$ in (i), we get

$y=-2(\dfrac{5}{2})^2+10(\dfrac{5}{2})-7$

$y=-2(\dfrac{25}{4})+\dfrac{50}{2}-7$

$y=\dfrac{-50}{4}+25-7$

$y=\dfrac{-25}{2}+18$

On further simplification, we get

$y=\dfrac{-25+36}{2}$

$y=\dfrac{11}{2}$

So, the vertex of the given quadratic equation is $\left(\dfrac{5}{2},\dfrac{11}{2}\right)$ .

Therefore, the correct option is A.

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2 years ago

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mylen [45]

Answer:

Step-by-step explanation:

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kkurt [141]

Answer:

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Step-by-step explanation:

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