4. Min = 22
Max = 60
Med = 34
Q1 = 25
Q3 = 48
5. Min = 68
Max = 100
Med = 85
Q1 = 72
Q3 = 96
Answer: The price for the computer = $1152
Step-by-step explanation:
Let the first boy = F
Let the second boy = S
Let the price of computer = C
The second boy had 5/ 6 of the money the first had. I.e
S = 5/6 F
Then F = 6/5S ......(1)
The first boy had 7 /8 of the price of the computer. That is
F = 7/8C ....... (2)
Substitute F in (1) into (2)
6/5S = 7/8C
S = 5/6 × 7/8C
S = 35/48C ......(3)
Together they had $696.00 more than they need to pay. That is
F + S = C + 696 ........ (4)
Substitute equation 2 and 3 into 4
7/8C + 35/48C = C + 696
0.875C + 0.729C = C + 696
0.604C = 696
C = 696/0.604
C = 1152 dollars
Therefore, the price for the computer = $1152
You would take the number of ice cream cups which is 12 and divide it by the cost which is 9.60
12/9.60=1.25
Since, the fundraiser only have three prices for books($2, $5 and $10), the number of $5 book that was sold is 12.
<h3>How to form equation and solve ?</h3>
The fundraiser only have 3 prices for books which are $2, $5 and $10.
There were 6 more $5 books sold than $10 books sold.
Let
x = number of $10 book sold
Therefore,
number of $5 books sold = x + 6
There are 8 more $2 book sold than $10 book sold. Therefore,
number of $2 books sold = x + 8
A total of $250 was raised.
Therefore, the total amount sold forms the following equation:
10x + 5(x + 6) + 2(x + 8) = 250
10x + 5x + 30 + 2x + 16 = 250
17x = 250 - 30 - 16
17x = 204
x = 204 / 17
x = 12
learn more on equation here: brainly.com/question/27361014
Lets have T be the TOTAL reduction
t = 7 * 0.02
t = 0.14
My answer here.
