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MAXImum [283]
2 years ago
9

30+5v i need help this a math question

Mathematics
2 answers:
ICE Princess25 [194]2 years ago
7 0

Answer:

35

Step-by-step explanation:

by

adding 30 to 5 and gives you 35

VMariaS [17]2 years ago
6 0

30+5v = 35v

hope this helps! :)

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<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B%282x%2B1%29%28x-5%29%7D%7B%28x-5%29%28x%2B4%29%5E%7B2%7D%20%7D" id
dybincka [34]

i) The given function is

f(x)=\frac{(2x+1)(x-5)}{(x-5)(x+4)^2}

The domain is

(x-5)(x+4)^2\ne 0

(x-5)\ne0,(x+4)^2\ne 0

x\ne5,x\ne -4

ii) For vertical asymptotes, we simplify the function to get;

f(x)=\frac{(2x+1)}{(x+4)^2}

The vertical asymptote occurs at

(x+4)^2=0

x=-4

iii) The roots are the x-intercepts of the reduced fraction.

Equate the numerator of the reduced fraction to zero.

2x+1=0

2x=-1

x=-\frac{1}{2}

iv) To find the y-intercept, we substitute x=0 into the reduced fraction.

f(0)=\frac{(2(0)+1)}{(0+4)^2}

f(0)=\frac{(1)}{(4)^2}

f(0)=\frac{1}{16}

v) The horizontal asymptote is given by;

lim_{x\to \infty}\frac{(2x+1)}{(x+4)^2}=0

The horizontal asymptote is y=0.

vi) The function has a hole at x-5=0.

Thus at x=5.

This is the factor common to both the numerator and the denominator.

vii) The function is a proper rational function.

Proper rational functions do not have oblique asymptotes.

6 0
3 years ago
( 1/2 ) RAISED TO -2 = ???
adelina 88 [10]

Answer:

answer is 4

1/2 ^ -2 = 4

 

8 0
3 years ago
Pls help I need it now
Marina CMI [18]

Answer:

I think the answer is C sorry if I'm wrong but hope I helped

5 0
3 years ago
Solve for all solutions of the equation: x^3 - 8 = 0
djyliett [7]

Answer:

x=2

Step-by-step explanation:

x^3=8

x=2  (take the cubed root of both sides)

This can be solved by adding 8 to both sides, then taking the cubed root of both sides

8 0
4 years ago
Simplify x0 y-3/x2 y-1
Natali5045456 [20]

Answer:

x^0 y^-3 / x^2 y^-1  

= 1 /  x^2 y^-1 (y^3)  ...because  x^0 = 1 and  [(y^-1) (y^3)] = y^2

= 1/(x^2 y^2)



6 0
3 years ago
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