Parallel sides of parallelogram are equal in length
AD=6x+14=6(6)+14=36+14=50
Option D
Answer:
Step-by-step explanation:
All we have to do is input the given values of x into the functions.
The first function:
f(x) = x^2 - 5x - 6
f(0) = 0^2 - 5(0) - 6 = 0 - 0 - 6 = -6
f(0) = -6
f(2) = 2^2 - 5(2) - 6 = 4 - 10 - 6 = -12
f(2) = -12
f(-1) = -1^2 - 5(-1) - 6 = 1 + 6 - 6 = 1
f(-1) = 1
f(6) = 6^2 -5(6) - 6 = 36 - 30 - 6 = 0
f(6) = 0
The second function:
f(x) = x^3 - x^2 - 12
f(0) = 0^3 - 0^2 - 12 = 0 - 0 - 12 = -12
f(0) = -12
f(2) = 2^3 - 2^2 - 12 = 8 - 4 - 12 = -8
f(2) = -8
f(-1) = -1^3 - (-1)^2 - 12 = -1 - 1 - 12 = -14
f(-1) = -14
f(6) = 6^3 - 6^2 - 12 = 216 - 36 - 12 = 168
f(6) = 168
The third function:
f(x) = 5 * 2^x
f(0) = 5 * 2^0 = 5 * 1 = 5
f(0) = 5
f(2) = 5 * 2^2 = 5 * 4 = 20
f(2) = 20
f(-1) = 5 * 2^-1 = 5 * 0.5 = 2.5
f(-1) = 2.5
f(6) = 5 * 2^6 = 5 * 64 = 320
f(6) = 320
Answer:
a=-1
If you need explanation please comment
Answer:
π\6
Step-by-step explanation:
The reference angle is the smallest angle measured from the terminal side of the angle (where the angle ends) to the x axis. The reference angle is an acute angle (i.e less than 90° or π/2)
For O = 11π/6 = 1.833π
1.833π is in the fourth quadrant between 3π/2 radians and 2π radians. Since it is in the fourth quadrant, the reference angle is given as:
reference angle = 2π - 11π/6 = π\6
