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Alex Ar [27]
2 years ago
14

Ben works at the Sudsy Scrubbers car wash. Last week, he recorded the number of cars he washed each day.

Mathematics
1 answer:
Vera_Pavlovna [14]2 years ago
4 0

Answer:

6 , 25 ,Range

Step-by-step explanation:

Option c is the right answer

I hope it helped you

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Suppose GRE Verbal scores are normally distributed with a mean of 461 and a standard deviation of 118. A university plans to rec
nirvana33 [79]

Answer:

The minimum score required for recruitment is 668.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 461 \sigma = 118

Top 4%

A university plans to recruit students whose scores are in the top 4%. What is the minimum score required for recruitment?

Value of X when Z has a pvalue of 1-0.04 = 0.96. So it is X when Z = 1.75.

Z = \frac{X - \mu}{\sigma}

1.75 = \frac{X - 461}{118}

X - 461 = 1.75*118

X = 667.5

Rounded to the nearest whole number, 668

The minimum score required for recruitment is 668.

8 0
2 years ago
which function results after applying the sequence of transformations to f(x)=x^5 reflect over the y axis ; shift 1 unit left ;
Morgarella [4.7K]
For this case we have the following function:
 f (x) = x ^ 5
 We apply the following transformations:
 reflect over the y axis:
 f (x) = (- x) ^ 5
 shift 1 unit left:
 f (x) = (- x + 1) ^ 5
 vertically compress by 1/3:
 f (x) = (1/3) (- x + 1) ^ 5
 Answer:
 
A function that results after applying the sequence of transformations is:
 
f (x) = (1/3) (- x + 1) ^ 5
6 0
3 years ago
Read 2 more answers
Determine the open intervals on which the graph of f(x) = x - 4cos x is concave upward or concave downward
bazaltina [42]

The graph of the function f(x) is

  • concave upward, when f''(x)>0;
  • concave downward, when f''(x)

Find f''(x):

1.

f'(x)=(x-4\cos x)'=1+4\sin x;

2.

f''(x)=4\cos x.

Now:

1. when 4\cos x>0, the graph of the function is concave upward and this is for

x\in \left(-\dfrac{\pi}{2}+2\pi k,\dfrac{\pi}{2}+2\pi k\right), \text{ where } k\in Z.

2.  when 4\cos x the graph of the function is concave downward and this is for

x\in \left(\dfrac{\pi}{2}+2\pi k,\dfrac{3\pi}{2}+2\pi k\right), \text{ where } k\in Z.

6 0
2 years ago
If 10% of men are bald, what is the probability that fewer than 100 in a random sample of 818 men are bald? (Answers must be in
Greeley [361]

Answer: the probability that fewer than 100 in a random sample of 818 men are bald is 0.9830

Step-by-step explanation:

Given that;

p = 10% = 0.1

so let q = 1 - p = 1 - 0.1 = 0.9

n = 818

μ = np = 818 × 0.1 = 81.8

α = √(npq) = √( 818 × 0.1 × 0.9 ) = √73.62 = 8.58

Now to find P( x < 100)

we say;

Z = (X-μ / α) = ((100-81.8) / 8.58) = 18.2 / 8.58 = 2.12

P(x<100) = P(z < 2.12)

from z-score table

P(z < 2.12) = 0.9830

Therefore the probability that fewer than 100 in a random sample of 818 men are bald is 0.9830

4 0
3 years ago
The diameter of a cone shaped is 4 in. Its height is 6 in. How much greater is the volume of a cylinder shaped container with th
nasty-shy [4]

The radius r used in below equations would equal 2in because it is half the given diameter of 4in.The volume of the cone would be The volume of a cylinder with the same dimensions would be the cylinder is 24 - 8 = 16 cubic inches greater.

5 0
3 years ago
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