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3 years ago

9

It takes Deanna seven hours to paint a fence. What fraction of the fence does she paint in one hour?

1 answer:

Serhud [2]3 years ago

5 0

Answer: 1/7

Step-by-step explanation:

From the question, we are informed that it takes Deanna seven hours to paint a fence. The fraction of the fence does she paint in one hour will be one divided by seven hours which can mathematically be written as:

= 1/7

This means that she'll paint 1/7 of the fence in 1 hour.

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Can you help me please?

Alecsey [184]

Answer:

The awnser is "The slope of line B is 4"

3 0

3 years ago

Read 2 more answers

At 55 mph it will take you approximately _____ feet to stop the car. A. 5 feet B. 100 feet C. 228 feet

ololo11 [35]

Answer:

The correct answer is option C, 228 feet

Step-by-step explanation:

As per Newton’s third law of motion:

V2 – U2 = 2 x a x S

Where V = final velocity

U = Initial Vlocity

a = acceleration (-ve)

S= distance travelled

V= 0 mph

U= 55 mph = 80.6667 ft /sec

0 – (80.6667 ft /sec)2 = 2 x (-g/2) x S

S = (80.6667 ft /sec)2 /(32.2 feet per second per second x0.5)

S = 202.1 feet

So the most nearest option is option C

6 0

3 years ago

Subtract: 4x/x^2-25 - 2/x^2+2x-15

Alex777 [14]

Answer: $\dfrac{4x^2-14x+10}{(x-5)(x+5)(x-3)}$

Step-by-step explanation:

Given

Subtract the expression

$\Rightarrow \dfrac{4x}{x^2-25}-\dfrac{2}{x^2+2x-15}\\\\\Rightarrow \dfrac{4x}{(x-5)(x+5)}-\dfrac{2}{x^2+5x-3x-15}\\\\\Rightarrow \dfrac{4x}{(x-5)(x+5)}-\dfrac{2}{(x+5)(x-3)}\\\\\text{Take the LCM and subtract}\\\\\Rightarrow \dfrac{4x(x-3)-2(x-5)}{(x-5)(x+5)(x-3)}\\\\\Rightarrow \dfrac{4x^2-12x-2x+10}{(x-5)(x+5)(x-3)}\\\\\Rightarrow \dfrac{4x^2-14x+10}{(x-5)(x+5)(x-3)}$

4 0

3 years ago

Plz help me with this math and also explain

jasenka [17]

Step-by-step explanation:

<h2>[1]</h2>

SI = $250
Rate (R) = 12 $\sf \dfrac{1}{2}$ %
Time (t) = 4 years

$\longrightarrow \tt { SI = \dfrac{PRT}{100} } \\$

$\longrightarrow \tt { 250 = \dfrac{P \times 12\cfrac{1}{2} \times 4}{100} } \\$

$\longrightarrow \tt { 250 = \dfrac{P \times \cfrac{25}{2} \times 4}{100} } \\$

$\longrightarrow \tt { 250 = \dfrac{P \times 25 \times 2}{100} } \\$

$\longrightarrow \tt { 250 = \dfrac{P \times 50}{100} } \\$

$\longrightarrow \tt { 250 \times 100 = P \times 50} \\$

$\longrightarrow \tt { 25000 = P \times 50} \\$

$\longrightarrow \tt { \dfrac{25000}{50} = P } \\$

$\longrightarrow \underline{\boxed{ \green{ \tt { \$ \; 500 = P }}}} \\$

Therefore principal is $500.

<h2>__________________</h2>

<h2>[2]</h2>

2/7 of the balls are red.
3/5 of the balls are blue.
Rest are yellow.
Number of yellow balls = 36

Let the total number of balls be x.

→ Red balls + Blue balls + Yellow balls = Total number of balls

$\longrightarrow \tt{ \dfrac{2}{7}x + \dfrac{3}{5}x + 36 = x} \\$

$\longrightarrow \tt{ \dfrac{10x + 21x + 1260}{35} = x} \\$

$\longrightarrow \tt{ \dfrac{31x + 1260}{35} = x} \\$

$\longrightarrow \tt{ 31x + 1260= 35x} \\$

$\longrightarrow \tt{ 1260= 35x-31x} \\$

$\longrightarrow \tt{ 1260= 4x} \\$

$\longrightarrow \tt{ \dfrac{1260 }{4}= x} \\$

$\longrightarrow \underline{\boxed{ \tt { 315 = x }}} \\$

Total number of balls is 315.

A/Q,

3/5 of the balls are blue.

$\longrightarrow \tt{ Balls_{(Blue)} =\dfrac{3 }{5}x} \\$

$\longrightarrow \tt{ Balls_{(Blue)} =\dfrac{3 }{5}(315)} \\$

$\longrightarrow \tt{ Balls_{(Blue)} = 3(63)} \\$

$\longrightarrow \underline{\boxed{ \green {\tt { Balls_{(Blue)} = 189 }}}} \\$

8 0

3 years ago

Let f(x) = -3x + 2 and g(x) = 2x – 5;<br> compute g(f(x))

ki77a [65]

Answer:

g(f(x)) = -6x+6.

Step-by-step explanation:

It is given that,

f(x) = -3x + 2 and g(x) = 2x – 5

We need to find g(f(x)).

Put it into g(x).

g(f(x)) = 2(-3x + 2)+2

= -6x+4+2

=-6x+6

Hence, the value of g(f(x)) is -6x+6.

8 0

2 years ago