Search it up and you shall find an answer believe me it is there
Ok, a=f/m
What we need to do is isolate the variable, m.
a=f/m
*m *m
a*m=f
m*a=f
/a /a
m=f/a
There's your answer.
Answer:
log(x^7·y^2)
Step-by-step explanation:
The applicable rules are ...
... log(a^b) = b·log(a)
... log(ab) = log(a) +log(b)
_____
The first term, 7log(x) can be rewritten as log(x^7). Note that an exponentiation operator is needed when this is written as text.
The second term 2log(y) can be rewritten as log(y^2). These two rewrites make use of the first rule above.
Now, you have the sum ...
... log(x^7) +log(y^2)
The second rule tells you this can be rewritten as ...
... log(x^7·y^2) . . . . . seems to match the intent of the 3rd selection
2=8x-2/9
add 2/9 to both sides
2 and 2/9=8x
2=18/9
2 and 2/9=18/9+2/9=20/9
20/9=8x
multiply both sides by 9
20=72x
divide boht isdes by 72
20/72=x=5/18
Alright, so 2x+2=0 (with x being the number) is what I'm getting from this. Subtract 2 from both sides to get 2x=-2, and then divide by 2 to get x=-1
