
It's already a square; we don't need to add anything to complete the square.

That's a vertex at x = -1. The corresponding y is y=0.
Answer: Vertex at (-1,0)
As for the other questions cut off there, the axis is the vertical line x = -1 and the range is y ≥ 0.
Given:
Consider the height of the rocket, in feet after x seconds of launch is

To find:
The time at which the rocket will reach its max, to the nearest 100th of a second.
Solution:
We have,

It is a quadratic polynomial with negative leading coefficient. So, it is a downward parabola.
Vertex of a downward parabola is the point of maxima.
To find the time at which the rocket will reach its max, we need to find the x-coordinate of the vertex.
If a quadratic function is
, then the vertex is

Here,
.
So,



So, x-coordinate of the vertex is 4.75.
Therefore, the rocket will reach its max at 4.75 second.
17= -13 -8x
+13
30=-8x
devide both sides by -8
-3.75 = x
x= -3.75
Answer:
i dont understand the qn..?
Step-by-step explanation: