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Dmitry [639]
2 years ago
7

Two integers a and b have a product of 12 what is the least possible sum of a and b?​

Mathematics
1 answer:
Eduardwww [97]2 years ago
3 0

Answer:

I think it is 7

Step-by-step explanation:

Because 3*4= 12 and 3+4=7 and those are the numbers that make the smallest sum that I can think of

Please Mark Brainlest

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natalie found a tennis ball outside a tennis court. she picked up the ball and threw it over the 12 foot fence into the court. t
olga55 [171]
The equation that gives the height is h(t) = - 16t^2 + 18t + 5, which is a parabola.


You cand find the maximum height from the vertex of the parabola.


Let's find the vertex. I will complete squares:

Start by extractin common factor -16:

-16t^2 + 18t + 5 = -16 [t^2 - (18/16) t - 5/16]


I will work with the expression inside the square brackets.

t^2 - (18/16)t - 5/16 = t^2 - (9/8) t - 5/16 =


Completing squares: (t - 9/16)^2 - (9 / 16 )^2 - 5/16

(t - 9/16)^2 - 81/ 256 - 5/16 = (t -9/16)^2 - 161/256


Now, include add include the factor -16[ (t- 9/16)^2 + 161/256 ] =

= -16 (t - 9/16)^2 + 161/16

That means that the vertex is 9/16, 161/16

So, the maximum height is 161 / 16 = 10,06, which is lower than the fence.


Answer: She will not make it over the fence.




4 0
2 years ago
The area of a square is (4x + 3)^2 square inches. The perimeter of the square is 172 inches. What is the value of x?
stepan [7]

Answer:

x = 10

Step-by-step explanation:

the area of a square = s² ( s is the side length )

s² = (4x + 3)² ( take the square root of both sides )

s = \sqrt{(4x+3)^2} = 4x + 3

perimeter = 4s = 172, that is

4(4x + 3) = 172 ( distribute left side )

16x + 12 = 172 ( subtract 12 from both sides )

16x = 160 ( divide both sides by 16 )

x = 10


4 0
3 years ago
Find the area of the equilateral triangle if a side is 8 squared root 3 m. Round to the nearest whole number. 67 m2 55 m2 28 m2
PilotLPTM [1.2K]

Answer:

The correct option is: 83 m²

Step-by-step explanation:

Side of an equilateral triangle: a = 8√3 m

Area of a triangle = 1/2 × base × height

Here, the height of the triangle = the length of the perpendicular bisector

Therefore, using the <u>Pythagoras theorem</u> to calculate the length of the perpendicular bisector of an equilateral triangle

a² = b² + c²

Here, hypotenuse of the smaller triangle: a = 8√3 m

base of the smaller triangle: b = a ÷ 2 = 8√3 ÷ 2 m = 4√3 m

and perpendicular bisector: c = ?

∴ a² = b² + c²

⇒ (8√3)² = (4√3)² + c²

⇒ c² = (8√3)² - (4√3)² = 192 - 48 = 144

<u>So, the height of the equilateral triangle</u>: c = √144 m = 12 m

and base of the equilateral triangle = 8√3 m

Therefore, the area of the equilateral triangle = 1/2 × base × height = 1/2 × 8√3 m × 12 m = 48√3 m² ≈ 83 m²

4 0
3 years ago
Segment DE is midsegment of triangle ABC. What is the length of segment DE?
DiKsa [7]
(X+5)2=X+15
2X+10=X+15
X=5
A) 5 :)
7 0
3 years ago
Read 2 more answers
Anybody want to help me with this problem ?
brilliants [131]
192x³ + 81
= 3(64x³ + 27)
= 3(4x + 3)(16x² - 12x + 9)  ← answer
5 0
2 years ago
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