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Leokris [45]
3 years ago
13

line passes through the point (-3,-4) and its y-intercept is (o, -9). What is the equation of the line that is parallel to the f

irst line and passes through the point (3, -7)?
Mathematics
1 answer:
12345 [234]3 years ago
7 0

Answer:

y=-\frac{5}{3}x-2

Step-by-step explanation:

The first line has a slope of -5/3 found using the points in the slope formula.

m=\frac{y_2-y_1}{x_2-x_1} =\frac{-9--4}{0--3}=\frac{-9+4}{0+3}=\frac{-5}{3}

Parallel lines have the same slope. So -5/3 is the slope of the second line. Write its equation using the point slope form y-y_1=m(x-x_1).

y--7=-\frac{5}{3}(x-3)\\y+7 = -\frac{5}{3}(x-3)\\y=-\frac{5}{3}x + 5 -7\\y=-\frac{5}{3}x-2

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Answer:

4p3 + 6p2 - 8p - 7

Step-by-step explanation:

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "p2"   was replaced by   "p^2".  1 more similar replacement(s).

STEP

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Equation at the end of step 1

 (((4 • (p3)) +  (2•3p2)) -  7) -  8p

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Equation at the end of step

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 ((22p3 +  (2•3p2)) -  7) -  8p

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Checking for a perfect cube

3.1    4p3+6p2-8p-7  is not a perfect cube

Trying to factor by pulling out :

3.2      Factoring:  4p3+6p2-8p-7

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  -8p-7

Group 2:  4p3+6p2

Pull out from each group separately :

Group 1:   (8p+7) • (-1)

Group 2:   (2p+3) • (2p2)

3.3    Find roots (zeroes) of :       F(p) = 4p3+6p2-8p-7

Polynomial Roots Calculator is a set of methods aimed at finding values of  p  for which   F(p)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  p  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  4  and the Trailing Constant is  -7.

The factor(s) are:

of the Leading Coefficient :  1,2 ,4

of the Trailing Constant :  1 ,7

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        3.00    

     -1       2        -0.50        -2.00    

     -1       4        -0.25        -4.69    

     -7       1        -7.00       -1029.00    

     -7       2        -3.50        -77.00    

     -7       4        -1.75        3.94    

     1       1        1.00        -5.00    

     1       2        0.50        -9.00    

     1       4        0.25        -8.56    

     7       1        7.00        1603.00    

     7       2        3.50        210.00    

     7       4        1.75        18.81    

Final result :

 4p3 + 6p2 - 8p - 7

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