Question

line passes through the point (-3,-4) and its y-intercept is (o, -9). What is the equation of the line that is parallel to the first line and passes through the point (3, -7)?

Answer 1

Answer:

$y=-\frac{5}{3}x-2$

Step-by-step explanation:

The first line has a slope of -5/3 found using the points in the slope formula.

$m=\frac{y_2-y_1}{x_2-x_1} =\frac{-9--4}{0--3}=\frac{-9+4}{0+3}=\frac{-5}{3}$

Parallel lines have the same slope. So -5/3 is the slope of the second line. Write its equation using the point slope form $y-y_1=m(x-x_1)$.

$y--7=-\frac{5}{3}(x-3)\\y+7 = -\frac{5}{3}(x-3)\\y=-\frac{5}{3}x + 5 -7\\y=-\frac{5}{3}x-2$