Answer:
Step-by-step explanation:
The trick is to find the third angle
180 - A - <BCA = <CBA
180 - X - <BCX = <CBX
Everything else is OK
<CBA = <CBX Equals equated to an equal express = an equal expression.
Now by a little slight of hand, you get the two triangles to be equal by ASA, which always works.
Cheating you say? There is no such thing as cheating if it correct and it works.
Answer:
I don't really know but one triangle is 180 degrees so two added together is 360 degrees...
but ohh I remembered
a=c+d (since a+b=180 and c+d+b=180)
e=g+h (since e+f=180 and g+h+f= 180)
and the fact is that c+d+g+h+b+f=the angle sum of quadrilateral PQRS
a+e+b+f= the angle sum of quadrilateral PQRS (by substitutions)
a+e+b+f=360 (four angles are from one origin so it's 360 degrees )
What you need to do is give these problems a common denominator. Which makes 3/21 and14/21 respectively. Logically, you need to walk 4/21 of the trail. This can’t be simplified further.
Add every side up and then subtract it by 180
Answer:
p(2p-11q+24p^6)
Step-by-step explanation:
