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olganol [36]
3 years ago
5

1. Solve the following equations on the interval {0 ≤ ≤ 2}. Round your answer to two decimal places where exact solutions are no

t possible.
a. cos+(√3)/2=0
b. 3(tan+1)=2
c. tan^2=121
d. 6sin^2−5cos−2=0
e. 3sin+3cos2=2
f. sin3=−(sqrt 3)/2
g. 8sin^2−8sin+1=0

Mathematics
1 answer:
Andrei [34K]3 years ago
3 0

HEY MATE ! Here is ur answer...

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6 0
3 years ago
9=4(s-3)<br><br> Help me what’s the correct answer?
kvv77 [185]

Answer:

 s=5 1/4

Step-by-step explanation:

Have a wonderful day

3 0
3 years ago
Factor 64-112w+49w^2
photoshop1234 [79]
49w² -112w + 64
first, you have to find 2 numbers that add up to equal -112, but also multiply together to get a product of 3136 (49 * 64)

two numbers that add to -112 and multiply to equal 3136 is -56 and -56
we can add them into the equation by putting them in for -112x

49w²-56w-56w+64

we now look at what the first 2 numbers have in common and what the last two numbers have in common
49w² and -56w both have w and 7 in common so we can divide 7w
7w(7w -8)
-56w and 64 both have -8 in common so we can divide by -8
-8(7w-8)
now we take the 2 numbers on the outside and bring down the numbers in the brackets

(7w-8)(7w-8)
(7w-8)²

7 0
3 years ago
You read 4 1/2 pages in 12 minutes. at the same rate, how many pages could you read in an hour?​
nignag [31]

Answer:

22.5 pages

Step-by-step explanation:

First divide the page number by the minutes it takes to read them to find pages per minute-

4.5 / 12 = .375

Then take that number and multiply it by the minutes in an hour-

(.375) (60) = 22.5

22.5 pages in one hour.

5 0
3 years ago
Read 2 more answers
An airplane has an air speed of 520 mph with a heading of 215 degrees. Find the plane's ground speed and course if it encounters
a_sh-v [17]
<span>Assuming east is positive x, north is positive y, break down the airplane's velocity into a vector in the x-y plane.
The plane is traveling 340 mph at a bearing of 210 degrees or (340cos(210), 340 sin(210)).
The wind is blowing from the west (to the east) at 50 mph or (50,0).
The actual ground speed would be the vector sum of those two (340 cos(210)+50, 340 sin(210)) or (-294.4+50,-170) or (-244.4,-170).
The magnitude of that velocity vector is




For direction



Since this angle is measured from the (-y) axis, we add 180 to get the actual heading.
The plane is traveling at 297.8 mph at a heading of 214.8 degrees. </span>

5 0
3 years ago
Read 2 more answers
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