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Papessa [141]
2 years ago
5

Please help Math it's a test

Mathematics
2 answers:
lozanna [386]2 years ago
7 0

Answer:

Yes

Step-by-step explanation:

For both 4/9 will be true.

dusya [7]2 years ago
3 0

Step-by-step explanation:

  1. yes
  2. yes

hope it helps ig...

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Drag each rational number to the correct location on the table.
andrey2020 [161]

Answer:

Step-by-step explanation:

Positive: -1/-3, -2/-2, +2/+3, -1/+3

the rest of them are negative

3 0
3 years ago
The coordinates of the vertices of triangle ABC are A(−3,3), B(−1,1), and C(−3,−2). The coordinates of the vertices of the image
Annette [7]
I believe your answer will be reflection

hope this helps
5 0
3 years ago
Read 2 more answers
using the midpoint formula find the coordinates of the midpoint 9f each sigment with end points (4,2),(-5,-1)​
exis [7]

Answer:

The midpoint of the segment is (-0.5,0.5).

Step-by-step explanation:

Midpoint of a segment:

The midpoint of a segment is given by the mean of its coordinates.

Segment with end points (4,2),(-5,-1)​

x-coordinates: 4 and -5

y-coordinates: 2 and -1

x-coordinate of the midpoint:

x = \frac{4-5}{2} = -\frac{1}{2} = -0.5

y-coordinate of the midpoint:

y = \frac{2-1}{2} = \frac{1}{2} = 0.5

The midpoint of the segment is (-0.5,0.5).

3 0
2 years ago
How did u get 4/3. Because I’m confused
Svet_ta [14]
What’s the original question and I can help!
5 0
3 years ago
Altitudes AA1 and BB1 are drawn in acute △ABC. Prove that A1C·BC=B1C·AC
Sophie [7]

Answer:

See the attached figure which represents the problem.

As shown, AA₁ and BB₁ are the altitudes in acute △ABC.

△AA₁C is a right triangle at A₁

So, Cos x = adjacent/hypotenuse = A₁C/AC ⇒(1)

△BB₁C is a right triangle at B₁

So, Cos x = adjacent/hypotenuse = B₁C/BC ⇒(2)

From (1) and  (2)

∴  A₁C/AC = B₁C/BC

using scissors method

∴ A₁C · BC = B₁C · AC

7 0
3 years ago
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