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Vinil7 [7]
3 years ago
6

Select the coordinates of two points on the line y = -2.

Mathematics
2 answers:
GaryK [48]3 years ago
5 0
Y=-2 is a horizontal line, each point which lies on this line has the y-coordinate -2.
Only in option C both points have the y-coordinate equal to -2.
The answer is C.
Dmitry [639]3 years ago
5 0

Answer:

The answer is C because -2 is located on the y-axis.

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E<br> Homework: 1-7 HW<br> Simplify the expression.<br> 8(5+t) - 2(t+1)<br> 8(5 + t) - 2(t+1)=
lys-0071 [83]

Hi, I'm happy to help!

To simplify this expression, we need to first use the order of operations <u>(Parenthesis, Exponents, Multiplication or Division (Left to Right), and Addition or Subtraction (Left to Right)</u>), then combine like terms. (<u>80,40,57</u>, or <u>6t, 8t, 98t</u>, or<u> 2t²,7t²,83t²</u>)

When a number is next to parenthesis with no sign, it means we are using multiplication. We can change this expression to look like this, by changing all the numbers next to the parenthesis with no sign, to one with a multiplication sign.

8(5+t) - 2(t+1) 8(5 + t) - 2(t+1)=

8×(5+t) - 2×(t+1)× 8×(5 + t) - 2×(t+1)=

We start with parenthesis and solve everything inside of those, but, because everything inside the parenthesis are unlike terms, we cannot combine them.

Next, We look for any exponents (x²). There are none in this equation.

We then look for multiplication or division. There is a lot of multiplication, so we start solving that from left to right.

8×(5+t) - 2×(t+1)× 8×(5 + t) - 2×(t+1)=

40+8t - 2×(t+1)× 8×(5 + t) - 2×(t+1)=

40+8t - 2×(t+1)× 8×(5 + t) - 2×(t+1)=

(40+8t) - (2t+2)× 8×(5 + t) - 2×(t+1)=

(40+8t) - (2t+2)× 8×(5 + t) - 2×(t+1)=

(40+8t) - (16t+16)×(5 + t) - 2×(t+1)=

(40+8t) - (16t+16)×(5 + t) - 2×(t+1)=

(40+8t) - (80t+16t²+80+16t) - 2×(t+1)=

(40+8t) - (80t+16t²+80+16t) - 2×(t+1)=

(40+8t) - (80t+16t²+80+16t) - (2t+2)=

(40+8t) - (80t+16t²+80+16t) - (2t+2)=

Now, before we do anything else, we need to recheck the parenthesis, now that they have changed. We can further simplify the middle parenthesis by adding together like terms.

(40+8t) - (80t+16t²+80+16t) - (2t+2)=

(40+8t) - ((80t+16t)+16t²+80) - (2t+2)=

(40+8t) - (96t+16t²+80) - (2t+2)=

(40+8t) - (96t+16t²+80) - (2t+2)=

Now, we look for addition or subtraction of like terms. We can now remove the parenthesis, since everything inside of the last two parenthesis is negative, we turn it negative, as long as we only combine the like terms.

40+8t - 96t-16t²-80 - 2t-2=

Once we find like terms, we can rearrange the expression.

(40-80-2)+8t - 96t+16t² - 2t

(-42)+8t - 96t-16t² - 2t

(-42)+8t - 96t-16t² - 2t

(-42)+(8t-96t-2t)-16t²

(-42)+(-90t)-16t²

(-42)+(-90t)-16t²

This doesn't have any like terms, so we don't alter it.

(122)+(-90t)-16t²

We can now remove the parenthesis.

122-90t-16t²

Since there are no more like terms this is the furthest we can simplify. We can then rearrange the expression to be arranged completely correct.

-16t²-90t-42

I hope this was helpful, keep learning! :D

4 0
3 years ago
Hansen won the raffle At the zoo and gets to feed the dolphins! The dolphin trainer gives Hansen a bucket of fish to divide even
Pachacha [2.7K]

Answer:

Number of dolphins in zoo * number of fish per dolphin.

Step-by-step explanation:

Hansen won the raffle At the zoo and gets to feed the dolphins! The dolphin trainer gives Hansen a bucket of fish to divide evenly among five dolphins. Each dolphin gets four fish. Which equation can you use to find the number of fish F in the bucket before hansen feeds them

Given that:

Number of dolphins = 5

Fish in bucket is distributed equally ; hence, Number of fish per dolphin = 4

To obtain the initial number of fish in bucket before hansen began to feed the fishes :

Number of fish in bucket before hansen feeds then :

Number of dolphins in zoo * number of fish per dolphin.

5 * 4 = 20

6 0
3 years ago
Can someone answer this
shepuryov [24]
Your answer for 15 is D or C. For 16 I’m estimating 125?
3 0
2 years ago
When is it helpful to estimate quotients?
pantera1 [17]
It is helpful to estimate quotients when the number is very big.
3 0
3 years ago
Which expressions are equivalent to 2 to the 11 power
STatiana [176]

\text{Hey there!}

\text{Which expressions are equivalent to}\bf{ \ 2^{11}}?

\bf{2^{11} = 2\times2\times2\times2\times2\times2\times2\times2\times2\times2\times2}

\bf{2\times2=4}\\\bf{2\times2=4}\\\bf{2\times2=4}\\\bf{2\times2=4}\\\bf{2\times2\times2 = 8}\\\bf{4\times4\times4\times4=16\times16=256}\\\bf{256\times8=2,048}\\\\\boxed{\boxed{\bf{Your\ answer: 2,048}}}\checkmark

\text{Good luck on your assignment and enjoy your day!}\\\\\frak{LoveYourselfFirst:)}

6 0
3 years ago
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