The volume, surface area and the ratios of the SA to volume will be as follows: Volume=πr²h Area=2πr²+πdh Ratio of SA to volume=Area/volume π=3.14 Thus using the above formula:
1. For the surface area to volume to be small it means that the area is smaller than the volume, for surface area to volume be larger it means that the surface area is larger than the volume. It is more economical for the surface area to volume to be small because it will mean that small amount of materials make cans with large volume. This means cost of production is cheaper.
2. To evaluate this process let's use one of the dimensions: Radius: 3 inches Height: 2 inches:
i. add radius and height: 3+2=5 inches ii. Multiply radius and height: 3×2=6 iii. Dividing the result from step 1 by the result in step 2: 5/6
iv. Multiply the result from step 3 by 2: 5/6×6 =5 This result does not seem to add up to the result in our earlier ratio. Thus we conclude that Khianna was wrong. This method can't work with 3-D figures.
What you need to do is find a common multiple which is 11, Then you divide 22c and 33d by 11 so you get 2c and 3d Then since there is an addition sign you put 2c and 3d is () The Final answer is 11(2c+3d)
