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Ulleksa [173]
2 years ago
9

In Mona’s new video game she earns 30 points for each fish caught and 80 points for each octopus captured, but she loses 15 poin

ts every time she captures a crab. Which expression represents the total number of points Mona will earn if she catches xfish, y octopi, and z crabs?

95(x+y-z)

110(x+y)-15z

30x+80y-15z

30+x+80+y-15+z
Mathematics
1 answer:
beks73 [17]2 years ago
6 0

Answer:

Third one

Step-by-step explanation:

30x would be 30 times the amount of fish (x)

+ 80y would be 80 times the amount of octopus captured (y)

- 15z would be subtracting 15 times the amount of crabs she captures

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Brainliest if correct
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Answer:

A.1/3

Step-by-step explanation:

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7 0
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You buy 6 pounds of apples for $33. what is the cost of 10 pounds of apples?
n200080 [17]
10 lbs of apples will cost $55

This is simple. First, you would need to find the unit rate, which is 5.5
You find the unit rate by simply dividing 33 by 6. Next, after you found your unit rate, you're going to multiply that by 10. We now know that 10 x 5.5= 55. Therefore, you will need $55 for 10 lbs of apples.

I hope I helped :)
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What's the value of x ? (I marked a random answer )
kondor19780726 [428]
X^2 = 60
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6 0
2 years ago
I need help please and i need work shown
velikii [3]

Answer:

<VUT = 50

Step-by-step explanation:

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3 0
2 years ago
Read 2 more answers
According to the U.S. Bureau of the Census, the average age of brides marrying for the first time is 23.9 years with a populatio
JulsSmile [24]

Answer:

We conclude that young women are delaying marriage and marrying at a later age.

Step-by-step explanation:

We are given that the average age of brides marrying for the first time is 23.9 years with a population standard deviation of 4.2 years.

The sociologist randomly samples 100 marriage records and determines the average age of the first time brides is 24.9 years.

Let \mu = <u><em>average age of brides marrying for the first time.</em></u>

So, Null Hypothesis, H_0 : \mu = 23.9 years     {means that young women are not delaying marriage and marrying at a later age}

Alternate Hypothesis, H_A : \mu > 23.9 years     {means that young women are delaying marriage and marrying at a later age}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                         T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample average age of the first time brides = 24.9 years

            \sigma = population standard deviation = 4.2 years

            n = sample of marriage records = 100

So, <u><em>the test statistics</em></u>  =  \frac{24.9-23.9}{\frac{4.2}{\sqrt{100} } }

                                     =  2.381

The value of z test statistics is 2.381.

<u>Now, at 1% significance level the z table gives critical value of and 2.326 for right-tailed test.</u>

Since our test statistic is more than the critical value of z as 2.381 > 2.326, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that young women are delaying marriage and marrying at a later age.

5 0
3 years ago
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