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vazorg [7]
3 years ago
10

When solving p2+5=8p-7, kate wrote p2+12=8p. The property she used is

Mathematics
1 answer:
Mkey [24]3 years ago
7 0

Answer:

She used the addition property of equality:

p2 + 5 = 8p - 7

     +7           +7

p2 + 12 = 8p

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Reflect polygon P using line L
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PLZ HURRY IT'S URGENT!!!!!!!!!!
ICE Princess25 [194]

\:  \:  \:  \frac{9}{12} \\  =   \frac{3 \times 3}{3 \times 4} \\  =  \frac{3}{4} \\  =  \frac{3}{4} \times 1 \\  =  \frac{3}{4} \times  \frac{2}{2} \\  =  \frac{6}{8} =  \frac{3}{4}.

So, Option C is the correct answer.

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Given r(x) = 11/ (x - 42)
julsineya [31]

For a given function f(x) we define the domain restrictions as values of x that we can not use in our function. Also, for a function f(x) we define the inverse g(x) as a function such that:

g(f(x)) = x = f(g(x))

<u>The restriction is:</u>

x ≠ 4

<u>The inverse is:</u>

y = 4 + \sqrt{\frac{11}{x} }

Here our function is:

f(x) = \frac{11}{(x - 4)^2}

We know that we can not divide by zero, so the only restriction in this function will be the one that makes the denominator equal to zero.

(x - 4)^2 = 0

x - 4 = 0

x = 4

So the only value of x that we need to remove from the domain is x = 4.

To find the inverse we try with the general form:

g(x) = a + \sqrt{\frac{b}{x} }

Evaluating this in our function we get:

g(f(x)) = a + \sqrt{\frac{b}{f(x)} }  = a + \sqrt{\frac{b*(x - 4)^2}{11 }}\\\\g(f(x)) = a + \sqrt{\frac{b}{11 }}*(x - 4)

Remember that the thing above must be equal to x, so we get:

g(f(x)) = a + \sqrt{\frac{b}{11 }}*(x - 4) = x\\\\{\frac{b}{11 }} = 1\\{\frac{b}{11 }}*4 - a = 0

From the two above equations we find:

b = 11

a = 4

Thus the inverse equation is:

y = 4 + \sqrt{\frac{11}{x} }

If you want to learn more, you can read:

brainly.com/question/10300045

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Find the sum. Enter your answer in simplest form.<br> 1/6+3/4
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