Write down all the possibilities when rolling a fair six sided die

Number five please help!

jeka57 [31]

Answer:

y+4 = 2(x+3)

Step-by-step explanation:

We have 2 points so we can find the slope

m = (y2-y1)/ (x2-x1)

= (2--4)/(0--3)

= (2+4)/(0+3)

= 6/3

= 2

We want to use the point slope form of the equation for a line

y-y1 = m(x-x1)

We know the slope =2 and the point (0,2)

y-2 = 2(x-0)

y-2 = 2x

We could also use the other point (-3,-4)

y--4 = 2(x--3)

y+4 = 2(x+3)

4 0

3 years ago

A cuboid in which the sum of its dimensions is 9 cm., then the sum of its edge lengths - cm. (18 or 27 or 36 or 45)

ser-zykov [4K]

The number of sides or edges on a cuboid are twelve, and the sum of the

edges is the sum of the twelve edges.

The sum of the edge lengths = 36 cm

Reasons:

The given parameters are;

The sum of the dimension of the cuboid = 9 cm

Required:

The value sum of the dimension of the edges the cuboid.

Solution:

The dimensions of a cuboid are; Length, l, width, w, and height, h

We get;

l + w + h = 9

The number of times that each dimension appear = 4 times

4 edges with the same length as the height, h

4 edges with the same length as the width, w

4 edges with the same length as the length, l

The sum of the edge lengths is therefore; Sum Edges = 4·l + 4·w + 4·h

Which gives;

Sum Edges = 4·l + 4·w + 4·h = 4 × (l + w + h) = 4 × 9 = 36

The sum of the edge lengths = 36 cm.

Learn more here:

brainly.com/question/12978944

5 0

2 years ago

According to the Knot, 22% of couples meet online. Assume the sampling distribution of p follows a normal distribution and answe

Ann [662]

Using the normal distribution and the central limit theorem, we have that:

a) The sampling distribution is approximately normal, with mean 0.22 and standard error 0.0338.

b) There is a 0.1867 = 18.67% probability that in a random sample of 150 couples more than 25% met online.

c) There is a 0.2584 = 25.84% probability that in a random sample of 150 couples between 15% and 20% met online.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1 - p)}{n}}$ , as long as $np \geq 10$ and $n(1 - p) \geq 10$ .