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Alexxandr [17]
3 years ago
9

6 The bar chart shows the A-level mathematics grades achieved by some students one year. A-level grades 120 100- 80 Frequency 60

40 20 om 0 A* A B D E U С Grade a How many students achieved grade B or C? b How many students took A-level mathematics? c Estimate the probability that a student will achieve grade B or C next year.​
Mathematics
1 answer:
skelet666 [1.2K]3 years ago
5 0

Answer:

very hard very hard

Step-by-step explanation:

other will answer it

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PQ = 6x + 25 and QR = 16 - 3x find PR
kondor19780726 [428]
6x+25=16-3x
+3x. +3x
9x + 25= 16
-25. -25
9x=-9
x=-1
7 0
3 years ago
Two machines are used for filling plastic bottles to a net volume of 16.0 ounces. A member of the quality engineering staff susp
aleksandrvk [35]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if the two machines are filling the bottles with a net volume of 16.0 ounces or if at least one of them is different.

The parameter of interest is μ₁ - μ₂, if both machines are filling the same net volume this difference will be zero, if not it will be different.

You have one sample of ten bottles filled by each machine and the net volume of the bottles are measured, determining two variables of interest:

Sample 1 - Machine 1

X₁: Net volume of a plastic bottle filled by the machine 1.

n₁= 10

X[bar]₁= 16.02

S₁= 0.03

Sample 2 - Machine 2

X₂: Net volume of a plastic bottle filled by the machine 2

n₂= 10

X[bar]₂= 16.01

S₂= 0.03

With p-values 0.4209 (for X₁) and 0.6174 (for X₂) for the normality test and using α: 0.05, we can say that both variables of interest have a normal distribution:

X₁~N(μ₁;δ₁²)

X₂~N(μ₂;δ₂²)

Both population variances are unknown you have to conduct a homogeneity of variances test to see if they are equal (if they are you can conduct a pooled t-test) or different (if the variances are different you have to use the Welche's t-test)

H₀: δ₁²/δ₂²=1

H₁: δ₁²/δ₂²≠1

α: 0.05

F= \frac{S^2_1}{S^2_2} * \frac{Sigma^2_1}{Sigma^2_2} ~~F_{n_1-1;n_2-1}

Using a statistic software I've calculated the test

F_{H_0}= 1.41

p-value 0.6168

The p-value is greater than the significance level, so the decision is to not reject the null hypothesis then you can conclude that both population variances for the net volume filled in the plastic bottles by machines 1 and 2 are equal.

To study the difference between the population means you can use

t= \frac{(X[bar]_1-X[bar]_2)-(Mu_1-Mu_2}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }  ~~t_{n_1+n_2-2}

The hypotheses of interest are:

H₀: μ₁ - μ₂ = 0

H₁: μ₁ - μ₂ ≠ 0

α: 0.05

Sa= \sqrt{\frac{(n_1-1)S^2_1+(N_2-1)S^2_2}{n_1+n_2-2}} = \sqrt{\frac{9*9.2*10^{-4}+9*6.5*10^{-4}}{10+10-2} } = 0.028= 0.03

t_{H_0}= \frac{(16.02-16.01)-0}{0.03*\sqrt{\frac{1}{10} +\frac{1}{10} } } = 0.149= 0.15

The p-value for this test is: 0.882433

The p-value is greater than the significance level, the decision is to not reject the null hypothesis.

Using a significance level of 5%, there is no significant evidence to reject the null hypothesis. You can conclude that the population average of the net volume of the plastic bottles filled by machine one and by machine 2 are equal.

I hope this helps!

8 0
4 years ago
Anyone good at math? Geometry in particular???
Gennadij [26K]
Am not good at that much but let me try
6 0
3 years ago
What is the equation that matches this table?
12345 [234]

Answer:

y = –1 + 3x

Step-by-step explanation:

To know which option is correct, we shall use the equation given in each option to see which will validate the table. This is illustrated below:

Option 1

y = –1x + 3

x = –2

y = –1(–2) + 3

y = 2 + 3

y = 5

This did not give the required value of y (i.e –7) in the table.

Option 2

y = 1 + 3x

x = –2

y = 1 + 3(–2)

y = 1 – 6

y = –5

This did not give the required value of y (i.e –7) in the table.

Option 3

y = –3 + 1x

x = –2

y = –3 + 1(–2)

y = –3 – 2

y = –5

This did not give the required value of y (i.e –7) in the table.

Option 4

y = –1 + 3x

x = –2

y = –1 + 3(–2)

y = –1 – 6

y = –7

This gives the required value of y (i.e –7) in the table.

Thus, the equation that matches the table is:

y = –1 + 3x

6 0
3 years ago
Solve the equation q/1.6=5
koban [17]

Answer:

q = 8

Step-by-step explanation:

To solve for q, you must isolate it.

In this case, you must isolate the q by multiplying 1.6 on both sides.

This makes the answer to be q = 8.

5 0
3 years ago
Read 2 more answers
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