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Genrish500 [490]
2 years ago
14

Let f (d) represent the amount of pennies that Jamie puts into the jar on day d. Today is day 0. Select the statement that is t

rue.
B. f(d+1)= 5(f(d))

C. f(d+1)= f(d)+1

D. f(d+1)= f(d)+5
Mathematics
1 answer:
Dovator [93]2 years ago
7 0

The correct statement that represents the arithmetic sequence for the amount of pennies that Jamie puts into the jar on day d is given by:

D. f(d+1)= f(d)+5

<h3>What is an arithmetic sequence?</h3>

In an arithmetic sequence, the difference between consecutive terms is always the same, called common difference d, hence, the relation can always be represented by:

f(n + 1) = f(n) + d

Researching the problem on the internet, it is found that:

  • On day 0, he puts 5 pennies.
  • On day 1, he puts 10.
  • On day 2, he puts 15, and so on...

Hence, the common difference is d = 15 - 10 = 10 - 5 = 5, and option D is correct.

More can be learned about arithmetic sequences at brainly.com/question/6561461

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kondor19780726 [428]

You have to combine like terms (terms that have the same variable(x,y....) and power/exponent)²³

(4x³ - 4 + 7x) - (2x³ - x - 8)        Distribute -1 into (2x³ - x - 8)

(4x³ - 4 + 7x) + (-)2x³ - (-)x - (-)8   (two negative signs cancel each other out and become positive)

(4x³ - 4 + 7x) - 2x³ + x + 8    Now combine like terms

4x³ - 2x³ + 7x + x - 4 + 8     (I rearranged for the like terms to be next to each other)

2x³ + 8x + 4       It is equivalent to B

(-3x^2+x^4+x)+(2x^4-7+4x)       Combine like terms

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(x² - 2x)(2x + 3)      Distribute x² into (2x + 3) and distribute -2x into (2x + 3)

(x²)2x + (x²)3 + (-2x)2x + (-2x)3

When you multiply a variable with an exponent by a variable with an exponent, you add the exponents together

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[Info]

When you multiply a variable with an exponent by a variable with an exponent, you add the exponents together. (You can combine the exponents only if they have the same variable)

For example:

x^{2} (x^3)=x^{(2+3)}=x^5

(y^3)x^2=y^3x^2         (You can't combine them because they have different exponents of y and x)

(5^2)(5^4)=5^{(2+4)}=5^6=15,625

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