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Julli [10]
3 years ago
10

Solve simultaneous equation....4x-5y and 2x+y=4

Mathematics
1 answer:
dsp733 years ago
8 0

Answer:

( \frac{20}{7}, - \frac{12}{7} )

Step-by-step explanation:

4x - 5y = 20 → (1)

2x + y = 4 → (2)

subtract 2x fro both sides in (2)

y = 4 - 2x → (3)

substitute y = 4 - 2x into (1)

4x - 5(4 - 2x) = 20 ( distribute parenthesis and simplify left side )

4x - 20 + 10x = 20

14x - 20 = 20 ( add 20 to both sides )

14x = 40 ( divide both sides by 14 )

x = \frac{40}{14} = \frac{20}{7}

substitute this value into (3)

y = 4 - 2(\frac{20}{7} ) = \frac{28}{7} - \frac{40}{7} = - \frac{12}{7}

solution is ( \frac{20}{7} , - \frac{12}{7} )

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