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3 years ago

If the manufacturer gains 6 %, the wholesale dealer 8% and the retailer 10 %. Then what

Mathematics

1 answer:

Alexandra [31]3 years ago

3 0

Answer:

The production cost is Rs 12,500

Step-by-step explanation:

Let the production cost be $x

At any point in time

sales price = cost price +( profit percentage* cost price)

Manufacturer gaining 6%

That would be;

x + 6% of x

x + 0.06x

= 1.06x

Wholesaler gaining 8%

= 1.06x + 8% of 1.06x

1.06x + 0.08(1.06x)

= 1.06x + 0.0848x

= 1.1448x

The for the retailer

= 1.1448x + 10% of 1.1448x

= 1.1448x + 0.11448x

= 1.25928x

1.25928x = 15,741

x = 15,741/1.25928

x = 12,500

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A tangent line and its normal line have a point of tangency to the function f(x) at (x,y). If the slop of the normal line is m=(

alekssr [168]

Answer:

$\displaystyle \\\left(\frac{49}{900},\frac{3761}{900}\right)$ or approximately (0.544, 4.179)

Step-by-step explanation:

A function and its tangent lines intersect when their slopes are the same. Find the x-coordinate when the slope of f(x) is equal to 8/7 by taking the derivative of f(x):

$\displaystyle\\f(x)=\sqrt{x}-x+4\\f'(x)=\frac{1}{2}\cdot\frac{1}{\sqrt{x}}-1=\frac{1}{2\sqrt{x}}-1$

Set $f'(x)$ equal to 8/7 and solve for x:

$\displaystyle \\\frac{1}{2\sqrt{x}}-1=\frac{8}{7},\\x=\frac{49}{900}$

Therefore, $f(x)$ will intersect at a point of tangency with a line of slope 8/7 at x=49/900. Plug in x=49/900 into $f(x)$ to get the y-coordinate:

$\displaystyle\\y=\sqrt{x}-x+4 \vert_{x=49/900}=\frac{3761}{900}$

⇒Answer: (49/900, 3761/900) or approximately (0.544, 4.179)

5 0

2 years ago

The gable end of the roof shown is divided in half by a vertical brace. Find the distance h (in ft) from an eave to the peak. 41

nlexa [21]

Answer:

h = 9 ft

Step-by-step explanation:

Assume the diagram is like the one below.

∆ABD is a right triangle.

We can use Pythagoras' Theorem to find the height h.

$\begin{array}{rcl}h^{2} + 40^{2} & = & 41^{2}\\h^{2} + 1600 & = & 1681\\h^{2} & = & 1681 - 1600\\& = &81\\h& = & \sqrt{81}\\&=& \mathbf{9}\end{array}\\\text{The height of the gable is $\large \boxed{\textbf{9 ft}}$}$

8 0

3 years ago

the length of a rectagle is 5 in longer than its width. if the perimeter of the rectangle is 58 in, find its length and width

dolphi86 [110]

Answer:

Length = 17 inches

Width = 12 inches

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Step-by-step explanation:

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As it is given that, the length of a rectangle is 5 in longer than its width and the perimeter of the rectangle is 58 in and we are to find the length and width of the rectangle. So,

⠀

Let us assume the width of the rectangle as x inches and therefore, the length will be (x + 5) inches .

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Now, According to the Question :

⠀

${\longrightarrow \qquad { \pmb{\frak {2 ( Length + Breadth )= Perimeter_{(Rectangle)} }}}}$