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2 years ago

Brainliest if correct

Mathematics

2 answers:

alina1380 [7]2 years ago

7 0

Combine like terms:

-5u + 5u = 0

The you are left with just -8

Answer: -8

Yuliya22 [10]2 years ago

4 0

Answer:

-8

Step-by-step explanation:

-5u+5u-8=(-5+5)u-8

=(0)u-8

=-8

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√secA+tanA/√secA-tanA × √cosecA-1/√cosecA+1=1

Snowcat [4.5K]

$Use:\\\\\sec A=\dfrac{1}{\cos A}\\\\\tan A=\dfrac{\sin A}{\cos A}\\\\\csc A=\dfrac{1}{\sin A}\\\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{\dfrac{a}{b}}=\dfrac{\sqrt{a}}{\sqrt{b}}\\---------------------------------\\\\\sec A+\tan A=\dfrac{1}{\cos A}+\dfrac{\sin A}{\cos A}=\dfrac{1+\sin A}{\cos A}\\\\\sec A-\tan A=\dfrac{1-\sin A}{\cos A}\\\\\csc A-1=\dfrac{1}{\sin A}-\dfrac{\sin A}{\sin A}=\dfrac{1-\sin A}{\sin A}\\\\\csc A+1=\dfrac{1+\sin A}{\sin A}$

$\dfrac{\sqrt{\sec A+\tan A}}{\sqrt{\sec A-\tan A}}\cdot\dfrac{\sqrt{\cos A-1}}{\sqrt{\cos A+1}}=1\\\\L_s=\sqrt{\dfrac{\sec A+\tan A}{\sec A-\tan A}\cdot\dfrac{\cos A-1}{\cos A+1}}=\sqrt{\dfrac{\frac{1+\sin A}{\cos A}}{\frac{1-\sin A}{\cos A}}\cdot\dfrac{\frac{1-\sin A}{\sin A}}{\frac{1+\sin A}{\sin A}}}\\\\=\sqrt{\dfrac{1+\sin A}{\cos A}\cdot\dfrac{\cos A}{1-\sin A}\cdot\dfrac{1-\sin A}{\sin A}\cdot\dfrac{\sin A}{1+\sin A}}\\\\\text{Everything are simplified}\\\\=\sqrt{1}=1=R_s$

7 0

3 years ago

How do i answer this question?

blondinia [14]

Answer:

$f^{-1}$ (59) = 20

Step-by-step explanation:

$f^{-1}$ (x) is the inverse of f(x)

to find the inverse function, let f(x) = y and rearrange to make x the subject.

y = 3x - 1 ( add 1 to both sides )

y + 1 = 3x ( divide both sides by 3 )

$\frac{y+1}{3}$ = x

change y back into terms of x with x = $f^{-1}$ (x) , then

$f^{-1}$ (x) = $\frac{x+1}{3}$ , then

$f^{-1}$ (59) = $\frac{59+1}{3}$ = $\frac{60}{3}$ = 20

7 0

3 years ago

Read 2 more answers

A rectangular parking lot has a perimeter of 820ft. The area of the Parking lot measures 42000 ft2. What is the width of the par

quester [9]

2W + 2L = 820
LW = 42,000 or L = 42,000/W 
substitute second equation into first equation: 
2W + 2(42,000/W) = 820 
2W + 84,000/W = 820 
2W^2/W + 84,000/W = 820W/W 
2W^2 - 820W + 84,000 = 0 
quadratic formula: 
W = [820 +/- SQR(672,400 - 4(2)(84,000))]/2(2) 
W = [820 +/- 20]/4 
W = 200, 210 
using second equation: 
L = 42,000/200, 42,000/210 = 210, 200 
The dimensions of the parking lot are 200ft by 210ft.

3 0

4 years ago

Read 2 more answers

Write the following as an inequality.

shepuryov [24]

The Answer is
-7 < W ≤ -3

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3 years ago

What is the quotient of 2 1/5 ÷ -1/10

Paraphin [41]

Answer:

-22