See attached for a sketch of some of the cross sections.
Each cross section has area equal to the square of the side length, which in turn is the vertical distance between the curve y = √(x + 1) and the x-axis (i.e. the distance between them that is parallel to the y-axis). This distance will be √(x + 1).
If the thickness of each cross section is ∆x, then the volume of each cross section is
∆V = (√(x + 1))² ∆x = (x + 1) ∆x
As we let ∆x approach 0 and take infinitely many such cross sections, the total volume of the solid is given by the definite integral,

Answer:
Graph D
Step-by-step explanation:
it does not pass the linear test to qualify as a function
Answer:
3(6+4) ._. hope this helps
This should help you here are the steps of your problem :)
2*(1/2)*r+2*r+1 = 9*(1/10) // - 9*(1/10)
2*(1/2)*r+2*r-(9*(1/10))+1 = 0
2*(1/2)*r+2*r-9/10+1 = 0
3*r+1/10 = 0 // - 1/10
3*r = -1/10 // : 3
r = -1/10/3
r = -1/30
r = -1/30
So your answer would be 1/30
It can be written as 1.0625