I hope this helps you
sec Q=1/cos Q
2=1/cos Q
cos Q= 1/2
Q=30+2.pi.n
Q=330+2.pi.n
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It’s only a vertical angle
Answer:
x = 2, y = -1.
Step-by-step explanation:
2x - 5y = 9
3x + 4y = 2
Multiply first equation by -3 and the second by 2:
-6x + 15y = -27
6x + 8y = 4 Adding the 2 equations:
23y = -23
y = -1.
Now substitute this value for y in the first equation:
2x - 5(-1) = 9
2x = 9 +5(-1)
2x = 9 - 5
2x = 4
x = 2.
Answer
a) k=7, h=9, the unique solution of the system is ![(x_1,x_2)=(1,1)](https://tex.z-dn.net/?f=%28x_1%2Cx_2%29%3D%281%2C1%29)
b) If k=6 and h=8 the system has infinite solutions.
c)If k=6 and h=9 the system has no solutions.
Step-by-step explanation:
I am assuming that the system is x1+3x2=4; 2x1+kx2=h
The augmented matrix of the system is
. If two times the row 1 is subtracted to row 2 we get the following matrix
.
Then
a) If k=7 and h=9, the unique solution of the system is
and solviong for
,
![x_1+3x_2=4\\\\x_1=4-3(1)=1](https://tex.z-dn.net/?f=x_1%2B3x_2%3D4%5C%5C%5C%5Cx_1%3D4-3%281%29%3D1)
Then the solution is ![(x_1,x_2)=(1,1)](https://tex.z-dn.net/?f=%28x_1%2Cx_2%29%3D%281%2C1%29)
b) If k=6 and h=8 the system has infinite solutions because the echelon form of the matrix has a free variable.
c)If k=6 and h=9 the system has no solutions because the last equation of the system of the echelon form of the matrix is ![0x_2=1](https://tex.z-dn.net/?f=0x_2%3D1)
Answer:
oh i is this 6th grade math im in 5th sorry
Step-by-step explanation: