All faces are rectangles.
Each two opposite faces are congruent and have the same area.
Two faces measure 20 cm by 7 cm.
Two faces measure 20 cm by 15 cm.
Two faces measure 15 cm by 7 cm.
total surface area = 2 * 20 cm * 7 cm + 2 * 20 cm * 15 cm + 2 * 15 cm * 7 cm
total surface area = 280 cm^2 + 600 cm^2 + 210 cm^2
total surface area = 1090 cm^2
again, bearing in mind that standard form for a linear equation means
• all coefficients must be integers, no fractions
• only the constant on the right-hand-side
• all variables on the left-hand-side, sorted
• "x" must not have a negative coefficient
![\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{-2})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{2}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{2-(-2)}{6-3}\implies \cfrac{2+2}{6-3}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-2)=\cfrac{4}{3}(x-3)\implies y+2=\cfrac{4}{3}x-4 \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx_1%7D%7B3%7D~%2C~%5Cstackrel%7By_1%7D%7B-2%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B6%7D~%2C~%5Cstackrel%7By_2%7D%7B2%7D%29%20%5C%5C%5C%5C%5C%5C%20slope%20%3D%20m%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%7B%20y_2-%20y_1%7D%7D%7B%5Cstackrel%7Brun%7D%7B%20x_2-%20x_1%7D%7D%5Cimplies%20%5Ccfrac%7B2-%28-2%29%7D%7B6-3%7D%5Cimplies%20%5Ccfrac%7B2%2B2%7D%7B6-3%7D%5Cimplies%20%5Ccfrac%7B4%7D%7B3%7D%20%5C%5C%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Bpoint-slope%20form%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y-y_1%3Dm%28x-x_1%29%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%5Cimplies%20y-%28-2%29%3D%5Ccfrac%7B4%7D%7B3%7D%28x-3%29%5Cimplies%20y%2B2%3D%5Ccfrac%7B4%7D%7B3%7Dx-4%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
Okay so here's how i think you solve it
both triangles have the same ratio, so set it as 3/4.5 (the smaller triangle) is equal to X/13.5 (the 9 added to the 4.5)
multiply 13.5/1 on both sides to get x alone
13.5 3
-------- x ------- = x x= 9
1 4.5
Answer:First, you must find the midpoint of the segment, the formula for which is
(
x
1
+
x
2
2
,
y
1
+
y
2
2
)
. This gives
(
−
5
,
3
)
as the midpoint. This is the point at which the segment will be bisected.
Next, since we are finding a perpendicular bisector, we must determine what slope is perpendicular to that of the existing segment. To determine the segment's slope, we use the slope formula
y
2
−
y
1
x
2
−
x
1
, which gives us a slope of
5
.
Perpendicular lines have opposite and reciprocal slopes. The opposite reciprocal of
5
is
−
1
5
.
We now know that the perpendicular travels through the point
(
−
5
,
3
)
and has a slope of
−
1
5
.
Solve for the unknown
b
in
y
=
m
x
+
b
.
3
=
−
1
5
(
−
5
)
+
b
⇒
3
=
1
+
b
⇒
2
=
b
Therefore, the equation of the perpendicular bisector is
y
=
−
1
5
x
+
2
.
Step-by-step explanation:
Answer:
(3, 2)
Step-by-step explanation:
y = 3x - 7
2x + 5y = 16
Solve for x:
2x + 5(3x - 7) = 16
2x + 15x - 35 = 16
17x = 51
x = 3
Solve for y:
y = 3(3) - 7
y = 9 - 7
y = 2
Answer:
(3, 2)
