3 years ago

These number groups all follow the same rule. What is the missing number?

Mathematics

1 answer:

Sonbull [250]3 years ago

7 0

Answer A

6-4=2, 2^2=4
So 7-3=4, 4^2=16

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Write the equation of a line that is perpendicular to y=2/7x +9 and that passes through the point (4,-6).

Allisa [31]

Answer:

$y=-\frac{7}{2}x+8$

Step-by-step explanation:

Given the equation

$y\:=\:\frac{2}{7}x+9$

comparing the equation with the slope-intercept form

$y =mx+b$

Here,

m is the slope

y is the intercept

so the slope of the line is 2/7

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line, so

the slope of the perpendicular line will be: -7/2

Therefore, the point-slope form of the equation of the perpendicular line that goes through (4,-6) is:

$y-y_1=m\left(x-x_1\right)$

$y-\left(-6\right)=\frac{-7}{2}\left(x-4\right)$

$y+6=\frac{-7}{2}\left(x-4\right)$

$y+6-6=\frac{-7}{2}\left(x-4\right)-6$

$y=-\frac{7}{2}x+8$

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