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laiz [17]
2 years ago
9

Evaluate 15/r when r=5

Mathematics
1 answer:
AveGali [126]2 years ago
7 0

Answer:

3

Step-by-step explanation:

\frac{15}{r} =\frac{15}{5}=3

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If sinx=5/13 and x is in quadrant 1, then sin x/2=
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Sin^-1(5/13) = 22.6

sin(22.6/2) = 0.196
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3 years ago
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PLEASE HELP FAST :(
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Write the equation of the line passing through the points (-7,5) and (-5,9):
y-5= \dfrac{9-5}{-5-(-7)} (x-(-7)) \\ y-5= \dfrac{4}{2}(x+7) \\ y-5=2(x+7).
You also have another two points (-3,13) and (-1,17). Look whether coordinates of these points satisfy the line equation:

1. For (-3,13) you have
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2. For (-1,17) you have
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4 0
2 years ago
Two times a number plus four is 22. What is the number?<br> 2<br> 6<br> 9<br> 11
34kurt

Answer:

9

Step-by-step explanation:

22-4 = 18 ("plus four")

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3 years ago
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If <img src="https://tex.z-dn.net/?f=x-12%5Csqrt%7Bx%7D%20%2B36%3D0" id="TexFormula1" title="x-12\sqrt{x} +36=0" alt="x-12\sqrt{
Elis [28]

Answer:

x = 36

Step-by-step explanation:

x - 12\sqrt{x} + 36 = 0

Subtract x and 36 from both sides.

-12\sqrt{x} = -x - 36

Divide both sides by -1.

12\sqrt{x} = x + 36

Square both sides.

144x = x^2 + 72x + 1296

Subtract 144x from both sides.

0 = x^2 - 72x + 1296

Factor the right side.

0 = (x - 36)^2

x - 36 = 0

x = 36

Since the solution of the equation involved squaring both sides, we musty check the answer for possible extraneous solutions.

Check x = 36:

x - 12\sqrt{x} + 36 = 0

36 - 12\sqrt{36} + 36 = 0

36 - 12\times 6 + 36 = 0

36 - 72 + 36 = 0

0 = 0

Since 0 = 0 is a true statement, the solution x = 36 is a valid solution.

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=18%20%7Bx%7D%5E%7B2%7D%20-%20x%20-%2039%20" id="TexFormula1" title="18 {x}^{2} - x - 39 " alt=
Anton [14]
I don’t know if you can solve it since it is an expression?
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3 years ago
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