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stiks02 [169]
3 years ago
8

At a military function, three cannons are fired at intervals of 12

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
3 0

Answer:

144 seconds

Step-by-step explanation:

To do solve this question, we must find the LCM (least common multiple) of 12, 16, and 18.

Let's start by prime factorizing (finding the prime factors) all the numbers.

12\rightarrow3*4\rightarrow2*2*3

16\rightarrow4*4\rightarrow2*2*2*2

18\rightarrow2*9\rightarrow2*3*3

Now, we must find the greatest quantity of each [prime] number and multiply them together to obtain the least common multiple.

Upon further evaluation of the [prime] factors, we can see that we need four 2s and two 3s. Therefore...

2*2*2*2*3*3=2^4*3^2=16*9=144

They will be fired together again after 144 seconds.

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If you roll one die and flip one coin, what is the probability of rolling a 2 and flipping a head? Why?
Nezavi [6.7K]

Answer:

Probability of rolling a 2 and flipping a head will be \frac{1}{12}    

Step-by-step explanation:

If we roll one die then probability to get any one side is \frac{1}{6}

Therefore, probability to get 2 by rolling the die will be P(A) = \frac{1}{6}

Now we flip a coin then getting head or tale probability is \frac{1}{2}

Or probability to get head by flipping the coin P(B) = \frac{1}{2}

Probability of happening both the events (rolling a 2 and flipping a head) will be denoted by

P(A∩B) = P(A)×P(B)

           = \frac{1}{6}\times \frac{1}{2}

           = \frac{1}{12}

Therefore, probability of rolling a 2 and flipping a head will be \frac{1}{12}        

3 0
4 years ago
Read 2 more answers
Hi please help ! this is rlly confusing! 15 points .
Bingel [31]
B. Quadrant 2 you can tell because point J is in the upper left quadrant.
4 0
3 years ago
Can someone help me urgently
cluponka [151]

Answer:

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Step-by-step explanation:

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8 0
4 years ago
URGENT!!! Solve the equation for the unknown
SCORPION-xisa [38]

\huge\boxed{ \boxed{ \mathrm{Answer࿐}}}

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_________________________

\mathrm{ ☠ \: TeeNForeveR \: ☠}

3 0
3 years ago
How do I do this Q11
SashulF [63]
Look at one of the vertices of the heptagon where two squares meet. The angles within the squares are both of measure 90 degrees, so together they make up 180 degrees.

All the angles at one vertex must clearly add up to 360 degrees. If the angles from the squares contribute a total of 180 degrees, then the two remaining angles (the interior angle of the heptagon and the marked angle) must also be supplementary and add to 180 degrees. This means we can treat the marked angles as exterior angles to the corresponding interior angle.

Finally, we know that for any convex polygon, the exterior angles (the angles that supplement the interior angles of the polygon) all add to 360 degrees (recall the exterior angle sum theorem). This means all the marked angles sum to 360 degrees as well, so the answer is B.
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3 years ago
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