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2 years ago

I need help with this question

Mathematics

1 answer:

Dafna1 [17]2 years ago

5 0

Answer:

no haha

Step-by-step explanation:

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What is the value of x? 4/5x-1/10=3/10?

Serhud [2]

Please note that in the original problem you have horizontal division symbols:

4 1 3
--- x - ---- = -----
5 10 10

On the other hand, you have typed 4/5x-1/10=3/10. To avoid ambiguity you must enclose the fractions inside parentheses:

(4/5)x- (1/10) = (3/10). Otherwise, your reader will not know for sure whether you meant 4 / (5x) or (4/5)x.

After you've typed in these parentheses, your next task is to mult. all the terms of this equation by 10, to remove the fractions. Result:

8x - 1 = 3, or 8x = 4, or x = 1/2 (answer)

3 0

4 years ago

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Help me pleaseeeeeeeeeee

velikii [3]

Answer:

I don't know iss shake eie

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3 years ago

Will give brainliest!!

dusya [7]

Answer:

b. 12

Step-by-step explanation:

2*2*2*2 - 8* 2 divided by 4= 12

8 0

3 years ago

How to solve an equation with two different variables.

77julia77 [94]

Answer:

Step-by-step explanation:

Move the variables to different sides of the equation. This "substitution" metho d starts out by "solving for x" (or any other variable) in one of the ...

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3 years ago

Three cards are drawn with replacement from a standard deck. What is the probability that the first card will be a diamond, the

noname [10]

Answer:

The probability that the first card will be a diamond, the second card will be a black card, and the third card will be a queen is 0.0096

Step-by-step explanation:

Total no. of cards = 52

No. of diamond cards = 13

No. of black cards = 26

No. of queens = 4

Three cards are drawn with replacement from a standard deck.

We are supposed to find he probability that the first card will be a diamond, the second card will be a black card, and the third card will be a queen

Probability of getting diamond card = $\frac{13}{52}$

Probability of getting black card = $\frac{26}{52}$

Probability of queen = $\frac{4}{52}$

Probability that the first card will be a diamond, the second card will be a black card, and the third card will be a queen = $\frac{13}{52} \times \frac{26}{52} \times \frac{4}{52}=0.0096$

Hence the probability that the first card will be a diamond, the second card will be a black card, and the third card will be a queen is 0.0096

3 0

4 years ago