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ELEN [110]
2 years ago
6

A company makes two products, A and B. Product A requires 12,5 hours of machining time and 30 minutes of finishing time per unit

. Product B requires 10 hours of machining time and one hour of finishing time per unit. There are 10000 hours and 600 hours available for machining and finishing respectively. Severe material shortages for the two products will limit their production to a maximum of 700 units for product A and 400 units for product B per day. If x and y are the number of units of product A and B produced per day respectively, choose the system of inequalities that describes the process.
Mathematics
1 answer:
Radda [10]2 years ago
6 0

The system of inequalities that describes the process is 12.5x + 10y ≤ 10000 and 0.5x + y ≤ 600

<h3>Inequality</h3>

Inequality is an expression that shows the non equal comparison of two or more variables and numbers.

Let x represent the number of products A and y represent the amount of product B, hence:

12.5x + 10y ≤ 10000 (1)

Also:

0.5x + y ≤ 600  (2)

The system of inequalities that describes the process is 12.5x + 10y ≤ 10000 and 0.5x + y ≤ 600

Find out more on Inequality at: brainly.com/question/24372553

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maks197457 [2]

Answer: 112°

Step-by-step explanation:

a straight line only has 180° at all times so it is a matter of subtraction. 180-68 is 112° so from there you can find #2 as 68°, #3 as 90° and #4 as 90°, and so on.

3 0
3 years ago
a dime is dropped from a building at 1.024 ft . if the equation for height as a function of time is h(t)=-16t^2+ initial height
babunello [35]

Answer:

The dime hits the ground after 8 sec.

Step-by-step explanation:

Set h(t) = -16t^2 + h(0) equal to 0:  -16t^2 + 1,024 ft = 0, or:

16t^2 = 1,024 ft, or:

 t^2 =  64 ft^2

Then t = +8 sec

The dime hits the ground after 8 sec.

7 0
3 years ago
Please help, simplify the polynomial 14x^2+4+3x-12x^2-3+11x
Misha Larkins [42]
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4 0
3 years ago
Y=arccos(1/x)<br><br> Please help me do them all! I don’t know derivatives :(
Stells [14]

Answer:

f(x) =  {sec}^{ - 1} x \\ let \: y = {sec}^{ - 1} x  \rightarrow \: x = sec \: y\\  \frac{dx}{dx}  =  \frac{d(sec \: y)}{dx}  \\ 1 = \frac{d(sec \: y)}{dx} \times  \frac{dy}{dy}  \\ 1 = \frac{d(sec \: y)}{dy} \times  \frac{dy}{dx}  \\1 = tan \: y.sec \: y. \frac{dy}{dx}  \\ \frac{dy}{dx} =  \frac{1}{tan \: y.sec \: y}  \\ \frac{dy}{dx} =  \frac{1}{ \sqrt{( {sec}^{2}   \: y - 1}) .sec \: y}  \\ \frac{dy}{dx} =  \frac{1}{ |x |  \sqrt{ {x }^{2}  - 1} } \\   \therefore  \frac{d( {sec}^{ - 1}x) }{dx}  =  \frac{1}{ |x |  \sqrt{ {x }^{2}  - 1} } \\ \frac{d( {sec}^{ - 1}5x) }{dx}  =  \frac{1}{ |5x |  \sqrt{25 {x }^{2}  - 1} }\\\\y=arccos(\frac{1}{x})\Rightarrow cosy=\frac{1}{x}\\x=secy\Rightarrow y=arcsecx\\\therefore \frac{d( {sec}^{ - 1}x) }{dx}  =  \frac{1}{ |x |  \sqrt{ {x }^{2}  - 1} }

4 0
2 years ago
Y= -3x^2-24x-46 write in vertex form
mario62 [17]

ANSWER

y= -3{(x + 4)}^{2}  + 2

EXPLANATION

The given function is:

y= -3x^2-24x-46

Factor -3 for the first 2 terms.

y= -3(x^2 + 8x)-46

We add and subtract the square of the coefficient of x.

y= -3(x^2 + 8x +  {(4)}^{2} )  - - 3( {4)}^{2} -46

Factor the perfect square trinomial.

y= -3 {(x + 4)}^{2} )  + 48 -46

The vertex form is:

y= -3{(x + 4)}^{2}  + 2

6 0
4 years ago
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