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Ivahew [28]
2 years ago
6

HELP NOWWW!! What is the quotient when 2 x 2 + 7 x – 15 is divided by 2 x – 3?

Mathematics
1 answer:
abruzzese [7]2 years ago
8 0

Answer:

yup 12

Step-by-step explanation:

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The first week of January there are 49 dogs and 28 cats in the shelter. Throughout the month the ratio of dogs to cats remains t
Katen [24]
There should be a total of 50 dogs if there’s 29 cats because -

6 0
3 years ago
PLEASE I HAVE AN HOUR Why might you use the distributive property to simplify 3(30-2)
gulaghasi [49]
Well, it would make the computation a lot easier:
Without the distributive property:
3 ( 30 - 2 ) =
3 ( 28 ) =
84.
I’m going to assume that you don’t know 3 ( 28 ) right off of the top of your head, so you can do:
3 ( 30 ) - 3 ( 2 ) =
90 - 6 =
84.
This way is much easier and less time consuming because you can do this computation in your head.
8 0
2 years ago
The population of a city is expected to increase by 3 percent next year. If p represents the population, write an expression to
fomenos

Answer:

The equation would be A = .03p

Step-by-step explanation:

To create this model, we know that we need to multiply the percentage by the current population. So we would multiply 3% or .03 by the variable given. You can set that equal to anything. I picked A for amount.

8 0
3 years ago
(a) consider the initial-value problem a=ka,a(0)=ao as t as the model for the decay of a radioactive substance. show that, in ge
mina [271]

The initial-value problem dA/dt = kA, A(0) = A₀ is used to represent the radioactive decay. The radioactive substance having half-life T= -(ln 2)/k,will take 2.5 T for the substance to decay from A₀ to A₀ / 6 .

a.) To solve this, we have the following differential equation:

dA/dt = kA

With the initial condition A(0) = A₀

Rewriting the differential equation like this:

dA/A = kdt

And if we integrate both sides we get:

ln |A| = kt + c₁

Where  is a constant. If we apply exponential for both sides we get:

A=e^{kt}e^{c} = C e^{kt}

Using the initial condition A(0) = A₀ we get ,

A₀ = C

So the solution for the differential equation is given by:

A(t) = A_{0}e^{kt}

For the half life we know that we need to find the value of t for where we have,

A(t) = 1/2 (A₀)

Using this we get ,

\frac{1}{2}A_{0} = A_{0}e^{kt

Cancel A₀ on both sides and applying log on both sides we get ,

ln(1/2) = kt

t = {ln(1/2) / k } ----(1)

And using the fact that  ln(1/2) = -ln(2)  we get,

t = - { ln(2) / k }

b.) To solve this we consider ,

A(t) = A_{0} e^{kt}

Replacing k with value obtained from 1 we get,

k = - {ln(2) / T}

A(t) = A_{0}e^{\frac{ln(2)}{T}t

Cancel the exponential with the natural log, we get,

A(t) = A_{0} 2^{-\frac{1}{T} }

c.)For this case we find the value of t when we have remaining A₀/6

So we can use the following equation:

A₀/6 =A_{0}2^{-\frac{t}{T} }

Simplifying we got:

1/6 = 2^{-\frac{t}{T} }

We can apply natural log on both sides and we got:

ln (1/6) = -t/T{ln(2)}

And if we solve for t we got:

t = T { ln(6) / ln(2) }

We can rewrite this expression like this:

t = T { ln(2²°⁵) / ln(2) }

Using properties of natural logs we got:

t = 2.5T { ln(2) / ln(2) }

t = 2.5T

Thus it will take 2.5 T for the substance to decay from A₀ to A₀/6 

Solve more problems on Half-life at :brainly.com/question/16439717

#SPJ4

5 0
1 year ago
Samantha saves at least 10% of the money she earns each month. She earns $120 each month for a year. Which inequality describes
viktelen [127]

Step-by-step explanation:

10 % each month is $12.00 12 months in a year 12 x 12.00 = $144.00

8 0
2 years ago
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