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Montano1993 [528]
4 years ago
15

Express the fractions 3/4,7/16 and 5/8 with LCD

Mathematics
1 answer:
Nikitich [7]4 years ago
4 0

The least common multiple of the three denominators is 16 because:

4 \times 4 = 16 \\ 16 \times 1 = 16 \\ 8 \times 2 = 16

Change the fractions so that each fraction has a denominator of 16.

\frac{3 \times 4}{4 \times 4} = \frac{12}{16}

\frac{7 \times 1}{16 \times 1} = \frac{7}{16}

\frac{5 \times 2}{8 \times 2} = \frac{10}{16}

____________________________________________________

1. \frac{12}{16} \\ \\ 2. \frac{7}{16} \\ \\ 3. \frac{10}{16}

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GarryVolchara [31]

Answer:

False

Step-by-step explanation:

40c - 300 = 40c + 200

-300 = 200

false

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3 years ago
Translate the following words into an expression:
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The answer Is A x+17 lol
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PSYCHO15rus [73]

Take some trinomial expansions to find some useful expressions and their values.

• 2nd degree expansion

x + y + z = 7 \\\\ \implies (x+y+z)^2 = x^2+y^2+z^2+2(xy+xz+yz) = 7^2 \\\\ \implies xy+xz+yz = \dfrac{49-33}2 = 8

• 3rd degree expansion

x+y+z=7 \implies (x+y+z)^3 = 7^3 \\\\ \implies \\ 243 = x^3+y^3+z^3+3(x^2y+x^2z+xy^2+y^2z+xz^2+yz^2) + 6xyz \\\\ \implies \\ x^2y+x^2z+xy^2+y^2z+xz^2+yz^2 + 2xyz = \dfrac{343 - 145}3 = 66

• 4th degree expansion

x+y+z=7 \implies (x+y+z)^4 = 7^4 \\\\ \implies \\ 2401 = x^4+y^4+z^4+4(x^3y+x^3z+xy^3+y^3z+xz^3+yz^3) \\\\ ~~~~~~~~~~~~+ 6(x^2y^2+x^2z^2+y^2z^2) + 12(x^2yz+xy^2z+xyz^2) \\\\ \implies \\\\ x^4+y^4+z^4 = 2401 - 4(x^3y+x^3z+xy^3+y^3z+xz^3+yz^3) \\\\ ~~~~~~~~~~~~~~~~~~~~~~- 6(x^2y^2+x^2z^2+y^2z^2) - 12(x^2yz+xy^2z+xyz^2)

Simplify:

x^3y+x^3z+xy^3+y^3z+xz^3+yz^3 \\\\ ~~~~ = x^2 (xy+xz) + y^2 (xy+yz) + z^2 (xz + yz) \\\\ ~~~~ = x^2 (xy+xz+yz) + y^2 (xy+xz+yz) + z^2 (xy + xz + yz) - (x^2yz + xy^2z + xyz^2) \\\\ ~~~~ = (x^2+y^2+z^2) (xy+xz+yz) - xyz (x+y+z) \\\\ ~~~~ = 264 - 7xyz

x^2y^2+x^2z^2+y^2z^2 \\\\ ~~~~ = xy\cdot xy + xz \cdot xz + yz \cdot yz \\\\ ~~~~ = xy(xy+xz+yz) + xz(xy+xz+yz) + yz(xy+xz+yz) - 2(x^2yz+xy^2z+xyz^2) \\\\ ~~~~ = (xy+xz+yz)^2 - 2xyz(x+y+z) \\\\ ~~~~ = 64 - 14xyz

x^2yz+xy^2z+xyz^2 = xyz (x + y + z) = 7xyz

Then the equation we got from the 4th degree expansion reduces to

x^4+y^4+z^4 = 2401 - 4(264-7xyz) - 6(64-14xyz) - 12(7xyz) \\\\ ~~~~~~~~~~~~~~~~~= 961 + 28xyz

and all we need now is the value of xyz.

In the 3rd degree expansion, we have

x^2y+x^2z+xy^2+y^2z+xz^2+yz^2 \\\\ ~~~~ = x(xy + xz) + y(xy + yz) + z(xz + yz) \\\\ ~~~~ = x(xy+xz+yz) + y(xy+xz+yz) + z(xy+xz+yz) - 3xyz \\\\ ~~~~ = (x+y+z)(xy+xz+yz) - 3xyz \\\\ ~~~~ = 56 - 3xyz \\\\ \implies (56 - 3xyz) + 2xyz = 66 \\\\ \implies xyz = -10

So, we end up with

x^4+y^4+z^4 = 961 - 280 = \boxed{681}

4 0
1 year ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B2%7D%20x%20-%20%20%5Cfrac%7B3%7D%7B4%7D%20x%20%3D%206" id="TexFormula1" ti
MAVERICK [17]

\frac{3}{2}x-\frac{3}{4}x=6

\frac{3}{2}x*4-\frac{3}{4}x*4=6*4

6x-3x=24

3x=24

\frac{3x}{3}=\frac{24}{3}

x=8

"x=8 is correct answer."

Hope this helps!

Thanks!

-Charlie

3 0
4 years ago
3z2−6z for z=5<br><br> Please help?!!
ludmilkaskok [199]

Answer:

3z+2= x ; z=5

3(5)+2

15+2

17

Step-by-step explanation:

5 0
3 years ago
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