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dangina [55]
3 years ago
5

What are symbols of inclusion

Mathematics
1 answer:
Kipish [7]3 years ago
5 0

Answer:

Symbols of inclusion are symbols used in mathematical expressions that group terms or factors together. They indicate that when we are simplifying expressions, we are to perform what's inside the symbols first. The three types of symbols of inclusion are parentheses, brackets, and braces.

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A minimum-phase continuous-time system has all its poles and zeros in the left-half s-plane. If a minimum-phase continuous-time
vlabodo [156]

Answer:

Yes, a minimum phase continuous time system is also minimum phase when converted into discrete time system using bilinear transformation.

Step-by-step explanation:

Bilinear Transform:

In digital signal processing, the bilinear transform is used to convert continuous time system into discrete time system representation.

Minimum-Phase:

We know that a system is considered to be minimum phase if the zeros are situated in the left half of the s-plane in continuous time system. In the same way, a system is minimum phase when its zeros are inside the unit circle of z-plane in discrete time system.

The bilinear transform is used to map the left half of the s-plane to the interior of the unit circle in the z-plane preserving the stability and minimum phase property of the system. Therefore, a minimum phase continuous time system is also minimum phase when converted into discrete time system using bilinear transformation.

8 0
3 years ago
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PLEASE HELP ASAP!!! A talent competition on television had five elimination rounds. After each elimination, only one-third of th
adelina 88 [10]

(9-243)/(4-1)=-78
D)−78 contestants per round, and it represents the average rate at which the number of contestants changed from the first round to the fourth roundReport · <span>14/12/2015</span>
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3 years ago
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Please I need 1,2, and 4
Virty [35]

Answer:what grade are you in?

Step-by-step explanation:

7 0
3 years ago
The value of the expression is
elixir [45]

Answer:

24

P: parentheses (12 - 8) = 4

E: exponents (3^2) = 9

M: multiplication (12-8)/2 * 4 = 8

D: division (12-8)/2 = 2

A: addition (7 + 9 + 8) = 24

S: subtraction (blank)

Following the order of operations, our final answer is: 24

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3 years ago
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$1500 is invested at a rate of 3% compounded monthly. Write a compound interest function to model this situation. Then find the
Marianna [84]

Answer:

<u>Equation</u>:  F=1500(1.0025)^{12t}

<u>The balance after 5 years is:  $1742.43</u>

<u></u>

Step-by-step explanation:

This is a compound growth problem . THe formula is:

F=P(1+\frac{r}{n})^{nt}

Where

F is future amount

P is present amount

r is rate of interest, annually

n is the number of compounding per year

t is the time in years

Given:

P = 1500

r = 0.03

n = 12 (compounded monthly means 12 times a year)

The compound interest formula modelled by the variables is:

F=1500(1+\frac{0.03}{12})^{12t}\\F=1500(1.0025)^{12t}

Now, we want balance after 5 years, so t = 5, substituting, we get:

F=1500(1.0025)^{12t}\\F=1500(1.0025)^{12*5}\\F=1500(1.0025)^{60}\\F=1742.43

<u>The balance after 5 years is:  $1742.43</u>

3 0
3 years ago
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