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defon
2 years ago
7

Use a net to find the surface area of the prism.

Mathematics
1 answer:
erik [133]2 years ago
8 0

Answer:

C. 516 in2

Step-by-step explanation:

I took the test last week and I got this question corrected

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Your friend gives you a simple regression fit for predicting house prices from square feet. the estimated intercept is –44850 an
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Answer:

  3022.08 . . . dollars per square meter

Step-by-step explanation:

The slope is multiplied by the factor that changes units:

  (280.76 dollars/ft²)×(1 ft²)/(.092303 m²) ≈ 3022.08 dollars/m²

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7 + r ≥ 18<br> Which is true?<br> 11<br> 10<br> 9
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11

Step-by-step explanation:

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A stereo store is offering a special price on a complete set of components (receiver, compact disc player, speakers, turntable).
Juli2301 [7.4K]

Answer:

a) 240 ways

b) 12 ways

c) 108 ways

d) 132 ways

e) i) 0.55

ii) 0.4125

Step-by-step explanation:

Given the components:

Receiver, compound disk player, speakers, turntable.

Then a purcahser is offered a choice of manufacturer for each component:

Receiver: Kenwood, Onkyo, Pioneer, Sony, Sherwood => 5 offers

Compact disc player: Onkyo, Pioneer, Sony, Technics => 4 offers

Speakers: Boston, Infinity, Polk => 3 offers

Turntable: Onkyo, Sony, Teac, Technics => 4 offers

a) The number of ways one component of each type can be selected =

\left(\begin{array}{ccc}5\\1\end{array}\right) \left(\begin{array}{ccc}4\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}4\\1\end{array}\right)

= 5 * 4 * 3 * 4  = 240 ways

b) If both the receiver and compact disk are to be sony.

In the receiver, the purchaser was offered 1 Sony, also in the CD(compact disk) player the purchaser was offered 1 Sony.

Thus, the number of ways components can be selected if both receiver and player are to be Sony is:

\left(\begin{array}{ccc}1\\1\end{array}\right) \left(\begin{array}{ccc}1\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}4\\1\end{array}\right)

= 1 * 1 * 3 * 4 = 12 ways

c) If none is to be Sony.

Let's exclude Sony from each component.

Receiver has 1 sony = 5 - 1 = 4

CD player has 1 Sony = 4 - 1 = 3

Speakers had 0 sony = 3 - 0 = 3

Turntable has 1 sony = 4 - 1 = 3

Therefore, the number of ways can be selected if none is to be sony:

\left(\begin{array}{ccc}4\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right)

= 4 * 3 * 3 * 3 = 108 ways

d) If at least one sony is to be included.

Number of ways can a selection be made if at least one Sony component is to be included =

Total possible selections - possible selections without Sony

= 240 - 108

= 132 ways

e) If someone flips switches on the selection in a completely random fashion.

i) Probability of selecting at least one Sony component=

Possible selections with at least one sony / Total number of possible selections

\frac{132}{240} = 0.55

ii) Probability of selecting exactly one sony component =

Possible selections with exactly one sony / Total number of possible selections.

\frac{\left(\begin{array}{ccc}1\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) + \left(\begin{array}{ccc}4\\1\end{array}\right) \left(\begin{array}{ccc}1\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) + \left(\begin{array}{ccc}4\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}3\\1\end{array}\right) \left(\begin{array}{ccc}1\\1\end{array}\right)}{240}

= \frac{(1*3*3*3)+(4*1*3*3)+(4*3*3*1)}{240}

\frac{27 + 36 + 36}{240} = \frac{99}{240} = 0.4125

5 0
3 years ago
Please help me, only answer if you know for sure
Galina-37 [17]

Answer:

Step-by-step explanation:

Median: First write in ascending order. If number of data's is odd, median is the middle data.

If number of data's is even, then median = average of n/2th and (n+2)/2th term.

1) 1 , 3 , 5 , 5 , 6

Median = 5

2) 3,4,10,2,1

Ascending order: 1,2,3,4,10

Median = 3

3) 4, 5,7,11

Median = (5+7)/2 = 12/2 = 6

4) 1,1,2,6

Median = (1+2)/2 = 3/2 = 1.5

5) 2,2,3,3,,5,7

Median = 3+3/2 = 6/2 = 3

6)1,2,4,6,7,7

Median = (4+6)/2 = 10/2 = 5

7) 2,2,3,6,7,8

Median = (3+6)/2 = 9/2 = 4.5

8)1,2,3,14,17,18

Median = (3+14)/2 = 17/2 = 8.5

Mean= Sum of all the items÷ number of items

1)Mean = (1+2+3+2)÷4 = 8÷2 = 4

2)Mean=(4+3+2+4+2)÷5 = 15÷5 = 3

3)Mean = (5+4+6+1)÷4 = 16÷4 = 4

4)Mean = (2+5+1+4+7+5)÷6 = 24÷6 = 4

5)Mean =(10+11+9+12+8)÷5=50÷5 = 10

6)Mean = (1 + 2 + (-2)+1+(-2) )÷5 = -2÷5 = -0.4

7)Mean = (4+(-2)+3+(-3)+3)÷5 = 5÷5 = 1

8)Mean = (4+5.5+3+5.5)÷4=18÷4 = 4.5

6 0
3 years ago
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