What is the area of the figure?<br> Enter your answer in the box.<br> in2

Select all the true statements about the number 3,600−−−−−√.

Paul [167]

Answer:

3,600−−−−−√ is a rational number.I guess

6 0

3 years ago

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Find a polynomial f(x) of degree 3 that has the following zeros.

Thepotemich [5.8K]

Answer:

$f (x) = x (x + 5) (x-9)$

Step-by-step explanation:

The zeros of the polynomial are all the values of x for which the function $f (x) = 0$

In this case we know that the zeros are:

$x = 9,\ x-9 =0$

$x = 0$

$x = -5$ , $x + 5 = 0$

Now we can write the polynomial as a product of its factors

$f (x) = x (x + 5) (x-9)$

Note that the polynomial is of degree 3 because the greatest exponent of the variable x that results from multiplying the factors of f (x) is 3

3 0

3 years ago

The coordinates of the vertices of a rectangle are (-4, 3), (-1, 5),(3, – 1), and (0, – 3).

SCORPION-xisa [38]

Answer:

Perimeter of rectangle is 23.34

Step-by-step explanation:

The coordinates of the vertices of a rectangle are (-4, 3), (-1, 5),(3, – 1), and (0, – 3).

What is the perimeter of the rectangle?

The formula to find perimeter of rectangle is: $Perimeter=2(l+w)$

We need to find length and width first using the coordinates (-4, 3), (-1, 5),(3, – 1), and (0, – 3).

Let A=(-4, 3) B=(-1, 5) C=(3, – 1) and D=(0, – 3) according to the figure attached.

So, If we find distance of point AB it can be considered length of rectangle and distance of point AC can be considered width of rectangle

The formula used to find distance is: $Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Finding distance AB, we have $x_1=-4, y_1=3, x_2=-1, y_2=5$

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance=\sqrt{(-1-(-4))^2+(5-3)^2}\\Distance=\sqrt{(-1+4)^2+(5-3)^2}\\Distance=\sqrt{(3)^2+(2)^2}\\Distance=\sqrt{9+4}\\Distance=\sqrt{13}\\Distance=3.61$

So distance between point A and B is 3.61

Finding distance AC, we have $x_1=-4, y_1=3, x_2=3, y_2=-1$

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance=\sqrt{(3-(-4))^2+(-1-3)^2}\\Distance=\sqrt{(3+4)^2+(-1-3)^2} \\Distance=\sqrt{(7)^2+(-4)^2} \\Distance=\sqrt{49+16} \\Distance=\sqrt{65}\\Distance=8.06$