THERE ARE 3 SANDWICHES, 3 SOUPS, 4 SALADS AND 2 DRINKS. IF EACH STUDENT HAD ONE OF EACH, HOW MANY DIFFERENT COMBINATIONS ARE POS
1 answer:
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Answer:
6 + 3 + 2
+
Step-by-step explanation:
Using the rule of radicals
×
⇔
Given
(3 + )(2 +
)
Each term in the second factor is multiplied by each term in the first factor, that is
3(2 + ) +
(2 +
) ← distribute both parenthesis
= 6 + 3 + 2
+
Answer:
- y=0.8x
- See Explanation for others
Step-by-step explanation:
The 3 cans of beans had a total weight of 2.4 Pounds
Therefore:
- 1 can of beans = (2.4 ÷ 3) =0.8 Pounds
The following applies from the options.
- y=0.8x where y is the weight and x is the number of cans.
- A 2-column table with 3 rows. Column 1 is labeled number of cans with entries 5, 15, 20. Column 2 is labeled total weight (in pounds) with entries 4, 12, 16.
Using y=0.8x
When x=5, y=0.8 X 5=4
When x=15, y=0.8 X 15=12
When x=20, y=0.8 X 20=16
- On a coordinate plane, the x-axis is labeled number of cans and the y-axis is labeled total weight (in pounds. A line goes through points (5, 4) and (15, 12). This can be clearly seen from the table above as (5,4) and (15,12) are points on the line.