Solve the quadratic equation by completing the square.
1 answer:
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Answer:
Step-by-step explanation:
Question 2
As far as I can see, you got it right. The general transformation for 90 ccw is
(x,y) ===> (-y, x)
What that means is for the x you put in -y changing the sign to the opposite and for the y you put in x and this time you leave the sign alone . The transformation is shown in the left hand diagram.
The two tables are shown below.
Original
- (1,4)
- (1,2)
- (3,2)
- (3,5)
The transformed table is
- (-4,1)
- (-2,1)
- (-2,3)
- (-5,3)
- (-4,1) This is just to let the program know to close the figure For some reason this did not have lines and if I delete it and put the lines in, I won't be able to upload the new diagram.
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Four
This one transforms from (x,y) to (-x,-y) which means where you see an x, you put a - x and where you see a y, you put a minus y. It is the middle frame.
Original
- (-4,3)
- (0,3)
- (-2,0)
- (-4,3) Here again, this is just to close the figure.
The transformed figure in red I think is
- (4,-3)
- (0,-3
- (2,0)
- (4,-3) And this closes the figure as well.
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Six
The diagram is on the right
Reflection about the y axis. Here the transformation is (x,y) ====> (-x,y) notice the ys don't change.
- (-3,0)
- (-5,-2)
- (-1,-2)
There is no closure.
Reflection
- (3,0)
- (5,-2)
- (1,-2)
Answer:
0.3009 is the probability that the applicant has graduate degree given he is a male.
Step-by-step explanation:
We are given he following in the question:
M: Applicant is male.
G: Applicant have a graduate degree
Total number of applicants = 450
Number of male applicants = 206
Number of applicants that are male and have a graduate degree = 62
We have to find the probability that the applicant has graduate degree given he is a male.
Thus, 0.3009 is the probability that the applicant has graduate degree given he is a male.
Answer:
mid point of AB (0.5 , 0)
Step-by-step explanation:
2x + 5y = 1 2x = 1 - 5y
y = 2xy+ 5 = (1 - 5y)*y + 5 = y - 5y² + 5
y-y = y - 5y² + 5 - y = - 5y² + 5
0 = - 5y² + 5
5y² = 5
y² = 1
y = 1 or y = -1
if y = 1 x = 1/2 (1 - 5) = -2 .... point A (-2 , 1)
if y = -1 x = 1/2 (1 + 5) = 3 ..... point B (3 , -1)
mid point of AB (x' , y') : x' = 1/2 (x₁ + x₂) = 1/2 (-2 + 3) = 1/2
y' = 1/2 (y₁ + y₂) = 1/2 (-1 + 1) = 0
