Question

What is the area of the trapezoid with height 13 units?

Answer 1

The equation for Area of Trapezoid is:

$Atrapezoid = \frac{h(b1+b2)}{2}$

First, replace the variables with their values:

h=13

b1=15

b2=(7+7)+15=29

Now, your equation should look like this:

$Atrapezoid = \frac{13(15+29)}{2}$

Now, solve:

$15+29=44$

↓

$\frac{13(44)}{2}$

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$44*13=572$

↓

$\frac{572}{2}=286$

The area of the trapezoid is 286.

Hope this helps! Please let me know if you need more help, or if you think my answer is incorrect. Brainliest would be MUCH appreciated. Have a great day!

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-$Kallmekris$

Answer 2

Answer:

286

Step-by-step explanation: