4y^3 - 2y^2
what is the largest number that divides evenly into 4y^3 and -2y^2?
it is 2
what is the highest degree of y that divides evenly into 4y^3 and -2y^2
it is y^2
the GCF is 2y^2
2y^2(2y - 1) <<<< answer
hope that helps, God bless!
Answer:
(x, y) = (1, -1)
Step-by-step explanation:
We'll write these equations in general form, then solve using the cross-multiplication method.
43x +67y +24 = 0
67x +43y -24 = 0
∆1 = (43)(43) -(67)(67) = -2640
∆2 = (67)(-24) -(43)(24) = -2640
∆3 = (24)(67) -(-24)(43) = 2640
These go into the relations ...
1/∆1 = x/∆2 = y/∆3
x = ∆2/∆1 = -2640/-2640 = 1
y = ∆3/∆1 = 2640/-2640 = -1
The solution is (x, y) = (1, -1).
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<em>Additional comment</em>
The cross multiplication method isn't taught everywhere. The attachment explains a bit about it. Our final relationship changes the order of the fractions to 1, x, y from x, y, 1. That way, we can use the equation coefficients in their original general-form order. (The fourth column in the 2×4 array of coefficients is a repeat of the first column.)
500-100=400
5(400)=2000
399+10=409
2000+409+2409
5(2409)=12045
3(12045)-36135
so in total it's equal to 36135
Answer:
its 3
Step-by-step explanation:
3+3=6
When you plot the points to the graph, the right angle is point A.