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nikdorinn [45]
3 years ago
5

Which choice is equivalent to the product below? Sqrt 3/16 x sqrt 3/9

Mathematics
1 answer:
Igoryamba3 years ago
4 0

Answer: 3/12

Step-by-step explanation:

ap£x ;)

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Find the measure of a regular 45 agon
lilavasa [31]

Answer:

172 degrees

Step-by-step explanation:

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3 years ago
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Which transformations are needed to change the parent cosine function to y= 3cos(10(x-pi) )?
denpristay [2]
<span>The parent cosine function can be transformed and translated. So, from the basic function cos(x) we can obtain function acos(bx+c). In our case, a=3- amplitude, b=10- the period change and c=-pi- the phase shift. So, the parent cosine function is mutiplied with 3 (which gives the amplitude of the function, 3*0.5=1.5). The period of the function is changed, and is 2pi/b=2pi/10=pi/5 and the cos(x) is phase shifted for c/b=-pi/10.</span>
6 0
3 years ago
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Determine the value of w and x in the figure below. (Thanks for the help I really appreciate it!)​
storchak [24]
Triangle HAM looks like an isosceles triangle, and we know that in an isosceles triangle 2 of the angles are the same.

so :
180 - 106 = 74 ( sum of the other 2 angles )
74/2 = 37 ( sum of angle HMA / HAM )

angles on a straight line add up to 180.
180-37=143 ( angle x )

since triangle YMH is also an isosceles,
180-37=143
143/2=71.5 ( angle w )
7 0
4 years ago
The height of a wooden pole, h, is equal to 20 feet. A taut wire is stretched from a point on the ground to the top of the pole.
kykrilka [37]

ANSWER

D. 25 feet

EXPLANATION

The height of the wall,h, the taut wire and the distance from the base of the pole to the point on the ground, formed a right triangle.

According to the Pythagoras Theorem, the sum of the length of the squares of the two shorter legs equals the square of the hypotenuse.

Let the hypotenuse ( the length of the ) taught wire be,l.

Then

{l}^{2}  =  {h}^{2}  +  {b}^{2}

{l}^{2}  =  {20}^{2}  +  {15}^{2}

{l}^{2}  =  400 + 225

{l}^{2}  =  625

l=  \sqrt{625}  = 25ft

8 0
3 years ago
What is the area of a rectangle if 1 base is 14 in, the 2nd base is 3.5 in and the height is 8 in?​
algol13

Check the picture below.

notice, we have three pair of sides, let's add them all up to get the area

\stackrel{\textit{left and right}}{2(8\cdot 14)}+\stackrel{\textit{front and back}}{2(3.5\cdot 8)}+\stackrel{\textit{top and bottom}}{2(3.5\cdot 14)}\implies 378~in^2

5 0
3 years ago
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