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erica [24]
3 years ago
14

a b) You are running around a rectangular ground of length 42 m and breadth 24 m. How many metres do you cover when you complete

6 rounds around it?​
Mathematics
2 answers:
prisoha [69]3 years ago
8 0

Answer:

792 m

Step-by-step explanation:

perimeter of a rectangle = 2l + 2b

⇒ perimeter of ground = (2 x 42) + (2 x 24) = 132 m

Perimeter = 1 round

⇒ 6 rounds = 6 x 132 = 792 m

Rainbow [258]3 years ago
4 0

Answer:

792 m

Step-by-step explanation:

First, calculate the perimeter.

= 2(42 + 24)

= 2(66)

= 132 m

Distance covered

= 132 x 6

= 792 m

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Answer:

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Step-by-step explanation:

This equation can simply be solved by adding 15 to both sides.

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A The length of a rectangle is 4 m more
Lady bird [3.3K]

Given :

  • The length of a rectangle is 4m more than the width.
  • The area of the rectangle is 45m²

⠀

To Find :

  • The length and width of the rectangle.

⠀

Solution :

We know that,

\qquad { \pmb{ \bf{Length \times Width = Area_{(rectangle)}}}}\:

So,

Let's assume the length of the rectangle as x and the width will be (x – 4).

⠀

Now, Substituting the given values in the formula :

\qquad \sf \: { \dashrightarrow x  \times  (x - 4) = 45 }

\qquad \sf \: { \dashrightarrow {x}^{2}  - 4x = 45 }

\qquad \sf \: { \dashrightarrow {x}^{2}  - 4x - 45 = 0 }

\qquad \sf \: { \dashrightarrow {x}^{2}    - 9x+ 5 x - 45 = 0 }

\qquad \sf \: { \dashrightarrow x(x - 9) + 5(x - 9) = 0 }

\qquad \sf \: { \dashrightarrow (x  - 9) (x  + 5) = 0 }

\qquad \sf \: { \dashrightarrow x = 9, \: \: x =  - 5}

⠀

Since, The length can't be negative, so the length will be 9 which is positive.

⠀

\qquad { \pmb{ \bf{ Length _{(rectangle)} = 9\:m}}}\:

\qquad { \pmb{ \bf{ Width _{(rectangle)} = 9 - 4=5\: m}}}\:

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

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2 years ago
Which expression is equivalent to
viva [34]

Answer:

C) x^{27} (\sqrt[3]{y} )

Step-by-step explanation:

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4 years ago
100 POINTS! I WILL GIVE BRAINLIEST! SHOW ALL WORK PLEASE!
pishuonlain [190]

Answer:

1. 2(3x−2)(2x−3)

2. 3(3x+1)(2x+5)

3. 2(4x+1)(2x−5)

4. 4(2x+1)(2x+7)

5. 5(3x+1)(2x−5)

6. 3(3x−7)(2x+1)

7. 3(5x+3)(3x−2)

8. 2(7x−2)(2x−5)

9. 2(7x−3)(2x−3)

10. 4(5x−11)(2x+1)

11. 5(x−2)(x+12)

12. (x−1)(x−8)

15. x=1 or x=4

Step-by-step explanation:

1. Factor 12x2−26x+12

12x2−26x+12

=2(3x−2)(2x−3)

2. 3(3x+1)(2x+5)

3. Factor 16x2−36x−10

16x2−36x−10

=2(4x+1)(2x−5)

4. Factor 16x2+64x+28

16x2+64x+28

=4(2x+1)(2x+7)

5. Factor 30x2−65x−25

30x2−65x−25

=5(3x+1)(2x−5)

6. Factor 18x2−33x−21

18x2−33x−21

=3(3x−7)(2x+1)

7. Factor 45x2−3x−18

45x2−3x−18

=3(5x+3)(3x−2)

8. Factor 28x2−78x+20

28x2−78x+20

=2(7x−2)(2x−5)

9. Factor 28x2−54x+18

28x2−54x+18

=2(7x−3)(2x−3)

10. Factor 40x2−68x−44

40x2−68x−44

=4(5x−11)(2x+1)

11. Factor 5x2+50x−120

5x2+50x−120

=5(x−2)(x+12)

12. Let's factor x2−9x+8

x2−9x+8

The middle number is -9 and the last number is 8.

Factoring means we want something like

(x+_)(x+_)

Which numbers go in the blanks?

We need two numbers that...

Add together to get -9

Multiply together to get 8

Can you think of the two numbers?

Try -1 and -8:

-1+-8 = -9

-1*-8 = 8

Fill in the blanks in

(x+_)(x+_)

with -1 and -8 to get...

(x-1)(x-8)

15. Let's solve your equation step-by-step.

(x−2)(x−3)=2

Step 1: Simplify both sides of the equation.

x2−5x+6=2

Step 2: Subtract 2 from both sides.

x2−5x+6−2=2−2

x2−5x+4=0

Step 3: Factor left side of equation.

(x−1)(x−4)=0

Step 4: Set factors equal to 0.

x−1=0 or x−4=0

x=1 or x=4

Sorry I wasn't able to do 13 and 14 but hope this helps! :)

8 0
3 years ago
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