<span>Based on the mentioned symptoms, the disorder that best describes his condition is Spontaneous pneumothorax and surgery is needed in order to overcome it. The presence of air in the form of small packs between the lungs and chest is a formal way of describing this condition and this may lead to damage in the lungs.</span>
The most common transfusion reaction, especially in patients lacking either IgA especially serum IgA, is the development of potentially severe hypersensitivity reactions or anaphylaxis. The most probable culprit is the presence of IgA in the transfused blood, because since the individual lacks IgA, then the IgA in the transfused blood is considered a foreign body triggering an allergic response.
It is possible to use the information of the nucleotide sequence of one strand to determine the sequence of the other strand.
- Deoxyribonucleic acid (DNA) is a biological molecule with two strands. Each strand is made up of a sequence of nucleotides. The DNA nucleotides are Adenine (A), Cytosine (C), Guanine (G) and Thymine (T).
- In a DNA molecule, Adenine forms an hydrogen bond with Thymine i.e. A-T, while Guanine forms an hydrogen bond with Cytosine i.e. G-C.
- Therefore, it is possible to use the information of the nucleotide sequence of one strand to determine the sequence of the other strand. For example, a strand with ATGCGTACGAT will form the following sequence: TACGCATGCTA
Learn more: brainly.com/question/2823802?referrer=searchResults
Answer:
50% or 1/2. The result remains unchanged if the husband were to have G6PD.
Explanation:
For X-linked recessive inheritance, a female (XX) needs two recessive alleles to be affected while a male needs only one (XY). It is hypothetically assumed that the Y chromosome does not carry any trait.
Assuming the allele for the disease is represented by g, a woman whose father suffered from G6PD is a carrier for the disease with genotype
. A normal man will have the genotype
. When the 2 marries:
x
=
It thus means that 50% or 1/2 of their sons will be expected to have G6PD.
Now, assuming the husband has G6PD, the mating becomes:
x
=
50% or 1/2 of their sons is still expected to have G6PD. The ratio remains unchanged.
It means that it is increasing speed on the chart