Answer:
8w^2 I don't know why it is not on here, but I put it in an algebra calculator and everything. Good luck. :)
Step-by-step explanation:
Simply the radicals by multiplying and taking square roots.
2![\sqrt[4]{8w^3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B8w%5E3%7D)
* ![\sqrt[4]{32w^5}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B32w%5E5%7D)
= 2 *2w![\sqrt[4]{2w}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2w%7D)
= 4w![\sqrt[4]{16w^4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16w%5E4%7D)
=4w(2w)
=
Ask me your other questions.i hope it was helpful
Answer:
D) {11,-4,-29}
Step-by-step explanation:
rewrite the equation as y= -5x+1 and plug in -2,1 and 6 to get y
-5*-2+1=11
-5*1+1=-4
-5*6+1=-29
When a number is 3 times a first number. A third number is 100 more than the first number and the sum of the three numbers is 450, the numbers are 70, 170 and 210.
<h3>How to calculate the numbers?</h3>
Let the first number = x
Second number = 3x
Third number = x + 100
Sum = 450
The numbers will be:
x + 3x + x + 100 = 450
5x + 100 = 450
5x = 450 - 100
5x = 350
Divide
x = 350 / 5
x = 70
First number = 70
Second number = 3x = 3 × 70 = 210
Third number = x + 100 = 70 + 100 = 170
Therefore, the numbers are 70, 170 and 210.
Learn more about numbers on:
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One number is 3 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 450 , find the numbers.
