Answer:
Step-by-step explanation:
This question is incomplete; here is the complete question.
A closed cylindrical can of fixed volume V has radius r. (a) Find the surface area, S, as a function of r. (b) What happens to the value of S approaches to infinity? (c) Sketch a graph of S against r, if V=10 cm³.
A closed cylindrical can of volume V is having radius r and height h.
a). Surface area of a cylinder is given by
S = 2(Area of the circular sides) + Lateral area of the can
S = 2πr² + 2πrh
S = 2πr(r + h)
b). Since surface area is directly proportional to radius of the can
S ∝ r
Therefore, when r approaches to infinity (r → ∞)
c). If V = 10 cm³ Then we have to graph S against r.
From the formula V = πr²h
10 = πr²h
h = 
By placing the value of h in the formula of surface area,
S = 
Now we can get the points to plot the graph,
r -2 -1 0 1 2
S -13.72 -13.72 0 26.28 35.13
Answer:
For the first one the answer is:
<K = 31°
Sorry I don't know the second one.
If a triangle has side lengths 5, 5, and 8, then the triangle should be classified as isosceles.
This is because an isosceles triangle has two sides of the same length and one side of a different length. This isn’t an equilateral triangle (where all sides are of equal length) or a scalene triangle (where all sides are of different lengths).
Hope this helps!
Answer:
If a scatter plot has no association then it's ordered pairs have no predictable pattern.
Step-by-step explanation:
Answer:
The GCF for the variable part is
k
Step-by-step explanation:
Since
18
k
,
15
k
3
contain both numbers and variables, there are two steps to find the GCF (HCF). Find GCF for the numeric part then find GCF for the variable part.
Steps to find the GCF for
18
k
,
15
k
3
:
1. Find the GCF for the numerical part
18
,
15
2. Find the GCF for the variable part
k
1
,
k
3
3. Multiply the values together
Find the common factors for the numerical part:
18
,
15
The factors for
18
are
1
,
2
,
3
,
6
,
9
,
18
.
Tap for more steps...
1
,
2
,
3
,
6
,
9
,
18
The factors for
15
are
1
,
3
,
5
,
15
.
Tap for more steps...
1
,
3
,
5
,
15
List all the factors for
18
,
15
to find the common factors.
18
:
1
,
2
,
3
,
6
,
9
,
18
15
:
1
,
3
,
5
,
15
The common factors for
18
,
15
are
1
,
3
.
1
,
3
The GCF for the numerical part is
3
.
GCF
Numerical
=
3
Next, find the common factors for the variable part:
k
,
k
3
The factor for
k
1
is
k
itself.
k
The factors for
k
3
are
k
⋅
k
⋅
k
.
k
⋅
k
⋅
k
List all the factors for
k
1
,
k
3
to find the common factors.
k
1
=
k
k
3
=
k
⋅
k
⋅
k
The common factor for the variables
k
1
,
k
3
is
k
.
k
The GCF for the variable part is
k
.
GCF
Variable
=
k
Multiply the GCF of the numerical part
3
and the GCF of the variable part
k
.
3
k
