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serg [7]
3 years ago
15

(a) Write down the gradient of the line with equation y = 7 - 4x The line L passes through the points with coordinates (- 3, 1)

and (2, - 2)
Mathematics
1 answer:
lesya [120]3 years ago
6 0

Note: Let us consider, we need to find the gradient of line L.

Given:

The given equation of a line is:

y=7-4x

The line L passes through the points with coordinates (- 3, 1) and (2, - 2).

To find:

The gradient of the given line and the gradient of line L.

Solution:

Slope intercept form of a line is:

y=mx+b                ...(i)

We have,

y=7-4x                   ...(ii)

On comparing (i) and (ii), we get

m=-4

Therefore, the gradient of the given line is -4.

The line L passes through the points with coordinates (- 3, 1) and (2, - 2). So, the gradient of line L is:

m=\dfrac{y_2-y_1}{x_2-x_1}

m=\dfrac{-2-1}{2-(-3)}

m=\dfrac{-3}{2+3}

m=\dfrac{-3}{5}

Therefore, the gradient of the line L is \dfrac{-3}{5}.

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Oksi-84 [34.3K]

Answer:

First blank is 15.

Second blank is 60.

Third blank is 8.

15x-60=8

Step-by-step explanation:

To clear the fractions, multiply both side by the least common multiple (or a common multiple) of the denominators you see.

The least common multiply of 4 and 5 is 4(5)=20.

So multiply both sides by 20:

20(\frac{3}{4}x-3)=20(\frac{2}{5})

\frac{3(20)}{4}x-3(20)=\frac{2(20)}{5}

Simplify:

3(5)x-60=2(4)

15x-60=8

First blank is 15.

Second blank is 60.

Third blank is 8.

7 0
3 years ago
Anyone know how to do this?
lesya [120]

<u>To solve this, we need to use our trignometric functions</u>;

   ⇒ <em>look at the diagram attached</em>

<em />

<u>Let's examine what the problem wants</u>:

  • hypotenuse (<em>longest side)</em> of the triangle

<u>Let's examine what the problem gives us</u>:

  • side adjacent to the 45-degree angle
  • angle that has measure of 45-degrees

<u>Let's solve</u>:

   sin(45)=\frac{5}{x} \\5=x*sin(45)\\x = \frac{5}{sin(45)} \\x=7.07

<u>Answer: 7.1</u> (<em>rounded to nearest tenth)</em>

<em />

Hope that helps!

6 0
2 years ago
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Consider the differential equation dydx=6x, dydx=6x, with initial condition y(0)=4y(0)=4.
topjm [15]
Formatting is kind of messed up. I'm assuming the differential equations is dy/dx = 6x

You need to get all the x's on one side and y'all on the other.

dy =6x dx

Integrate both sides.

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y(0) = 4 = 3(0)^2 + C

C = 0

y = 3x^2

Plug 1 in for x to find the value of y(1)

y(1) = 3(1)^2 = 3







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The answer is 180 if right
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