Note: Let us consider, we need to find the gradient of line L.
Given:
The given equation of a line is:

The line L passes through the points with coordinates (- 3, 1) and (2, - 2).
To find:
The gradient of the given line and the gradient of line L.
Solution:
Slope intercept form of a line is:
...(i)
We have,
...(ii)
On comparing (i) and (ii), we get

Therefore, the gradient of the given line is -4.
The line L passes through the points with coordinates (- 3, 1) and (2, - 2). So, the gradient of line L is:




Therefore, the gradient of the line L is
.