Question

The relationship between the intensity of sound((w)/(m^(2)))and the distance from the source of sound is represented by the equation (i)=((k)/(d^(2))).If you sit only one meter away from the stage at a rock concert the intensity of sound is about 0.1(w)/(m^(2)). If vanessa does not want the sound intensity to be more than 0.001(w)/(m^(2)) how close to the stage can she sit?

Answer 1

Answer:

10 m

Step-by-step explanation:

We are given that the relationship between intensity of sound and distance from the source is given by

Intensity (I)=$\frac{k}{d^2}$

Where I=Intensity

d=Distance of sound from the source

If distance d=1m

Intensity, I=0.1$w/m^2$

We have to find how close she can to the stage if vanessa does not want the sound intensity to be more than 0.001(w)/(m^(2)).

Using the formula

$0.1=\frac{k}{1}$

$k=0.1$

$\frac{0.1}{d^2}\leq 0.001$

$\frac{0.1}{0.001d^2}\leq 1$

$\frac{0.1}{0.001}\leq d^2$

$100\leq d^2$

$10\leq d$

$d=10 m$

Hence, she can sit 10 m away from the stage.