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Ghella [55]
2 years ago
11

Why was Aristarchus’s model not accepted? Select two options.

SAT
2 answers:
julia-pushkina [17]2 years ago
3 0

It was not accepted because at the time it was believed that the earth was at the center of the universe.

AlexFokin [52]2 years ago
3 0

<em>monetizing</em><em> </em><em>hunch</em><em> </em><em>goose</em><em> </em><em>food</em><em> </em><em>this</em><em> </em><em>duha</em><em> </em><em>effort</em><em> </em><em>to</em><em> </em><em>spend</em><em> </em><em>da</em><em> </em><em>of</em><em> </em><em>SMP</em><em> </em><em>over</em><em> </em><em>Gmod</em><em> </em><em>an</em><em> </em><em>fond</em><em> </em><em>usually</em><em> </em><em>just</em><em> </em><em>loves</em><em> </em><em>Thakkar</em><em> </em><em>often</em><em> </em><em>concern</em><em> </em><em>of</em><em> </em><em>his</em><em> </em><em>ex</em><em> </em><em>PC</em><em> </em><em>DCC</em><em> </em><em>he</em><em> </em><em>will</em><em> </em><em>d,</em><em> </em><em>EC</em><em> </em><em>HL</em><em> </em><em>en</em><em> </em><em>PC</em><em> </em><em>EC</em><em> </em><em>HL</em><em> </em><em>sa</em><em> </em><em>if</em><em> </em><em>Dec</em><em> </em><em>HL</em><em> </em><em>on</em><em> </em><em>endrol</em><em> </em><em>global</em><em> </em><em>seem</em><em> </em><em>dee</em><em> </em><em>to</em><em> </em><em>Dec</em><em> </em><em>up</em><em> </em><em>go</em><em> </em><em>to</em><em> </em><em>to</em><em> </em><em>v</em><em> </em><em>if</em><em> </em><em>we</em><em> </em><em>en</em><em> </em><em>ta</em><em> </em><em>en</em><em> </em><em>all</em><em> </em><em>ok</em><em> </em><em>too</em><em> </em><em>of</em><em> </em><em>all</em><em> </em><em>falls</em><em> </em><em>all</em><em> </em><em>so</em><em> </em><em>can</em><em> </em><em>k</em><em> </em><em>cc</em><em> </em><em>all</em><em> </em><em>so</em><em> </em><em>happy</em><em> </em><em>fall</em><em> </em><em>guess</em><em> </em><em>human</em><em> </em><em>theory</em>

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If sin(1/x^2+1) is an antiderivative for f(x) then.
STatiana [176]

The limit from 1 to 2 of the given antiderivative is; -0.19865

<h3>What is the Limit of the Integral?</h3>

We are given the antiderivative of f(x) as sin(1/(x² + 1)). Thus, to find the limit from 1 to 2, we will solve as;

\int\limits^2_1 {(sin\frac{1}{x^{2} + 1} )} \, dx = {(sin\frac{1}{2^{2} + 1} )}  - {(sin\frac{1}{1^{2} + 1} )}

⇒ (sin ¹/₅) - (sin ¹/₂)

⇒ 0.19866 - 0.47942

⇒ -0.19865

Complete Question is;

If sin(1/(x² + 1)) is an anti derivative for f(x), then what is the limit of f(x)dx from 1 to 2?

Read more about integral limits at; brainly.com/question/10268976

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Lol, i use this app not to ask any questions that should be asked.​
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