Why was Aristarchus’s model not accepted? Select two options.

SAT

2 answers:

julia-pushkina [17]2 years ago

3 0

It was not accepted because at the time it was believed that the earth was at the center of the universe.

AlexFokin [52]2 years ago

3 0

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13. Disposal of waste is one of the major concerns which is affecting the environment. Which of the following methods can be use

bagirrra123 [75]

Answer:

D: recycling

Explanation:

By minimizing the use of disposable items and promoting the use of recycled articles.

Separating biodegradable and non-biodegradable waste before dumping them.

Recycling the non-biodegradable waste material.

5 0

3 years ago

a helicopter flies parallel to the ground at an altitude of 1/2 kilometer and at a speed of 2 kilometers per minute. if the heli

Murrr4er [49]

The Pythagoras' theorem and the uniform motion allows to find the answer for the rate of change of distance is

v = 32.3 m / s

The distance is the length of the segment that a white house wing with the helicopter, this can be found using the Pythagoras' theorem

R = $\sqrt{x^2 + y^2}$

Where R is the distance, x is the horizontal distance where the helicopter flies and y is the vertical distance that corresponds to the flight height

y = 500 m

Since the helicopter flies at constant speed, we can use the uniform motion relation

$v_h$ = $\frac{x}{t}$

x = $v_h$ t

Where $v_h$ is the speed of the helicopter and t is the time

We substitute

r = $\sqrt {(V_h \ t)^2 + y^2}$

Kinematics defines velocity as the change of position in the unit of time

$v = \frac{dR}{dt}$

$v = \frac{1}{2} \ \frac{2 ( v_h t) v_h}{ \sqrt{(v_h t)^2 + y^2} }$

$v = \frac{v_h^2 \ t}{ \sqrt{(v_h t)^2 + y^2} }$

This expression is the change in distance as a function of time for a given speed. In the exercise, this speed is requested for a time of one minute, for the helicopter speed of

v = 2km/min ( $\frac{1000m}{1km}$ ) ( $\frac{1 min}{60s}$ ) = 33.33 m / s