Answer: I think that if it accidentally spreads to areas where it is unwanted, it will be difficult to remove.
Answer:
about half that of the Canadian dollar.
Explanation:
Answer:
The body temperature of a male at the 83rd percentile is 98.8°F.
Explanation:
The <em>n</em>th percentile implies that there are <em>n%</em> value below this percentile value.
That is, if P (<em>X </em><<em> x</em>) = n% then <em>x</em> is the <em>n</em>th percentile.
Let<em> </em><em>X</em> = male body temperature.
The random variable <em>X</em> follows a Normal distribution with mean, <em>μ</em> = 98.4°F and standard deviation, <em>σ</em> = 0.40°F.
Let <em>x</em> be the 83rd percentile value.
Then, P (X < x) = 0.83.
The value of <em>x</em> can be computed from the <em>z</em>-score.
![z=\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
Compute the <em>z</em>-score related to this probability as follows:
P (Z < z) = 0.83
*Use the <em>z</em>-table for the <em>z</em>-score.
The value of <em>z</em> is 0.95.
Compute the value of <em>x</em> as follows:
![z=\frac{x-\mu}{\sigma}\\0.96=\frac{x-98.4}{0.40} \\x=98.4+(0.96\times0.40)\\=98.784\\\approx98.8](https://tex.z-dn.net/?f=z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5C%5C0.96%3D%5Cfrac%7Bx-98.4%7D%7B0.40%7D%20%5C%5Cx%3D98.4%2B%280.96%5Ctimes0.40%29%5C%5C%3D98.784%5C%5C%5Capprox98.8)
Thus, the body temperature of a male at the 83rd percentile is 98.8°F.
Answer:I say online
Explanation:
Because it’s quick and easy