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Wewaii [24]
2 years ago
12

100 points FOR BOTH!!! PLEASE PLEASE PLEASE HELP

Mathematics
2 answers:
Zepler [3.9K]2 years ago
6 0
Answer
60^0

Explain
VOW=90^0-30^0
=60^0

Now
Therefore VOW=YOZ
YOZ=60^0[vertical opposite angle]
velikii [3]2 years ago
4 0

Answer:

60 degrees

Step-by-step explanation:

Angle XOV = 90 degrees (given)

Angle WOX = 30 degrees (given)

Therefore angle WOV = 90-30 = 60

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36=2+(-12.4)<br> please helpssss
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I believe the answer is 36= -10.4!
Sorry if I'm wrong though.
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A school has 300 students. If the ratio of boys to girls is 31 to 44, how many girls are there in the school?
Shalnov [3]

Answer:

176 girls

Step-by-step explanation:

31+44 = 75

300/75 = 4

4*44 = 176

176 girls in the school

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Joan has raised $306 by selling 34 equally priced boxes of chocolate for the team fund-raiser. Which of the following equations
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The first one ore third one.
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In ΔDEF, the measure of ∠F=90°, FD = 75 feet, and EF = 95 feet. Find the measure of ∠D to the nearest tenth of a degree. (Plz an
meriva

Answer:

  51.7°

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you that ...

  Tan = Opposite/Adjacent

  tan(D) = EF/FD = 95/75

  D = arctan(95/75)

  ∠D ≈ 51.7°

6 0
3 years ago
Thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village are approximately normally
sasho [114]

Answer:

a) P(X

P(z

b) P(X>7.0)=P(\frac{X-\mu}{\sigma}>\frac{7-\mu}{\sigma})=P(Z1.47)

P(z>1.47)=1-P(z

c)  P(3

P(-0.882

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the thickness of a population, and for this case we know the distribution for X is given by:

X \sim N(4.5,1.7)  

Where \mu=4.5 and \sigma=1.7

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using excel or the normal standard table:

P(z

Part b

We are interested on this probability

P(X>3.0)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>7.0)=P(\frac{X-\mu}{\sigma}>\frac{7-\mu}{\sigma})=P(Z1.47)

And we can find this probability using excel or the normal standard table:

P(z>1.47)=1-P(z

Part c

P(3

And we can find this probability using excel or the normal standard table liek this:

P(-0.882

3 0
3 years ago
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